Chapter 6, Problem 6.55P

Interpretation Introduction

Interpretation:

Determine the enthalpy change and entropy change for propane gas if it is compressed isothermally.

Concept Introduction:

The enthalpy and entropy changes are calculated as:

  $\Delta H={\displaystyle \underset{T_1}{\overset{T_2}{\int }}{C}_P{}^{ig}dT+}{H}_2{}^R-H_1{}^R$

Where, $H^R={\left(H^R\right)}^0+\omega {\left(H^R\right)}^1$....(1)

And

  $\Delta S={\displaystyle \underset{T_1}{\overset{T_2}{\int }}{C}_P{}^{ig}\frac{dT}{T}-R\ln \frac{P_2}{P_1}+}{S}_2{}^R-S_1{}^R$

Where, $S^R={\left(S^R\right)}^0+\omega {\left(S^R\right)}^1$....(2)