The equation is given and Edmister’s formula for calculation of acentric factor should be derived as, ω = 3 7 θ 1 − θ log P c − 1 ..(a) Concept Introduction: The acentric factor is defined as: ω = − 1.0 − log ( P r s a t ) T r = 0.7 ....(b) First convert the given equation into reduced temperature and pressures terms and then replace the constants also in terms of reduced conditions and normal boiling point condition. Find the value of P r s a t from it and put it on above equation.

Question

Want to see the full answer?

Answer 1

Question

Chapter 6, Problem 6.16P

Interpretation Introduction

Interpretation:

The equation is given and Edmister’s formula for calculation of acentric factor should be derived as,

ω=37θ1−θlogPc−1

..(a)

Concept Introduction:

The acentric factor is defined as:

ω=−1.0−log(Prsat)Tr=0.7

....(b)

First convert the given equation into reduced temperature and pressures terms and then replace the constants also in terms of reduced conditions and normal boiling point condition. Find the value of Prsat from it and put it on above equation.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

← Homework 8 View Policies Show Attempt History Current Attempt in Progress A liquid mixture of benzene and toluene containing 52.0 wt% benzene at 100.0 °C and pressure Po atm is fed at a rate of 32.5 m³/h into a heated flash tank maintained at a pressure Ptank Material Balances Correct. 0.67/1 === Attempts: 1 of 5 used Calculate Ptank (atm), the mole fraction of benzene in the vapor, and the molar flow rates of the liquid and vapor products. Ptank .544 atm Ybz .657 mol benzene/mol vapor product nvapor 55.8 mol/s nliquid 37.6 mol/s Hint GO Tutorial Energy Balance Check heat capacities. Calculate the required heat input rate in kilowatts. i 0.447 kW Hint GO Tutorial Save for Later Assistance Used Attempts: 2 of 5 used Assistance Used Attempts: 1 of 5 used Submit Answer

View Policies Show Attempt History Current Attempt in Progress Homework 8 A stream of pure cyclopentane vapor flowing at a rate of 1650 L/s at 190.0°C and 1 atm enters a cooler in which 50.0% of the feed is condensed at constant pressure. Question 4 of 5 Correct What is the temperature at the condenser outlet? 49.3 °℃ eTextbook and Media Hint Enthalpy Table Your Answer Correct Answer (Used) 0.67/1 E Attempts: 1 of 5 used Prepare and fill in an inlet-outlet enthalpy table. Use a reference state of liquid cyclopentane at the boiling point. In T = 190.0°C Out T=49.3°C Substance n (mol/s) Ĥ (kJ/mol) n (mol/s) Ĥ (kJ/mol) C5H10(1) 0.0 21.708 0.0 C5H10(V) 43.416 43.687 21.708 27.30 Heat Check significant figures and sign. Calculate the required cooling rate (a positive number). ! kW Hint Save for Later Attempts: 3 of 5 used Submit Answer

View Policies Show Attempt History Current Attempt in Progress A liquid mixture of benzene and toluene containing 52.0 wt% benzene at 100.0 °C and pressure Po atm is fed at a rate of 32.5 m³/h into a heated flash tank maintained at a pressure Ptank Your answer is partially correct. 1.312 atm Assistance Used 0.58/1 Calculate Ptank (atm), the mole fraction of benzene in the vapor, and the molar flow rates of the liquid and vapor products. Ptank i atm .657 Ybz mol benzene/mol vapor product nvapor 55.8 mol/s nliquid 37.6 mol/s Hint GO Tutorial Save for Later Energy Balance Calculate the required heat input rate in kilowatts. i kW GO Tutorial Save for Later Assistance Used Attempts: 1 of 5 used Submit Answer Assistance Used Attempts: 0 of 5 used Submit Answer