Process Dynamics and Control, 4e
Process Dynamics and Control, 4e
4th Edition
ISBN: 9781119285915
Author: Seborg
Publisher: WILEY
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Chapter 6, Problem 6.8E
Interpretation Introduction

(a)

Interpretation:

The most accurate transfer function Cout(s)Cin(s) for the given process is to be developed.

Concept introduction:

For chemical processes, dynamic models consisting ordinary differential equations are derived through unsteady-state conservation laws. These laws generally include mass and energy balances.

The process models generally include algebraic relationships which commence from thermodynamics, transport phenomena, chemical kinetics, and physical properties of the processes.

For a function f(t), the Laplace transform is given by,

F(s)=L[f(t)]=0f(f)estdt

Here, F(s) represents the Laplace transform, s is a variable which is complex and independent, f(t) is any function of time which is being transformed, and L is the operator which is defined by an integral.

f(t) is calculated by taking inverse Laplace transform of the function F(s).

The difference in the actual variable (y) and the original variable (y¯) is known as deviation variable (y). It is generally used while modelling a process. Mathematically it is defined as:

y=yy¯

In steady-state process, the accumulation in the process is taken as zero.

Interpretation Introduction

(b)

Interpretation:

Approximated low order transfer function for the given system is to be determined.

Concept introduction:

For higher order transfer function approximation, higher order models are approximated using the time delays into lower order models of approximate similar dynamics and steady-state characteristics. Formula used for this approximation is:

eθs=1eθs=11+θs

Provided the value of θ is very small.

Interpretation Introduction

(c)

Interpretation:

The conclusion regarding the need to model the mixing characteristics of the transfer pipe very accurately for this process is to be made.

Concept introduction:

For chemical processes, dynamic models consisting ordinary differential equations are derived through unsteady-state conservation laws. These laws generally include mass and energy balances.

The process models generally include algebraic relationships which commence from thermodynamics, transport phenomena, chemical kinetics, and physical properties of the processes.

Interpretation Introduction

(d)

Interpretation:

For a step change in cin, the approximate and the full order model responses are to be simulated.

Concept introduction:

For chemical processes, dynamic models consisting ordinary differential equations are derived through unsteady-state conservation laws. These laws generally include mass and energy balances.

The process models generally include algebraic relationships which commence from thermodynamics, transport phenomena, chemical kinetics, and physical properties of the processes.

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For each set of measurements below, calculate the Grubbs statistic, G, look up the appropriate critical value of G from Table 4.6, and determine whether the Grubbs test supports discarding the first value in the list at the 95% level of confidence. a) 106.0, 165.0, 167.5, 170.5, 163.5, 170.7 (Geale -2.028; Gerit 1.822; yes, the Grubbs test supports discarding 106.0) b) 214.8, 263.0, 229.9, 236.9, 221.8, 230.8, 241.1 c) 357.0, 309.3, 304.9, 314.8, 305.8, 295.3, 284.7, 299.5 TABLE 4-6 Critical values of G for rejection of outlier Number of observations otsulsve os Tenos nagsibarito G to buboxy (95% confidence) 456 1.463 1.672 1.822 7 1.938 8 upa 2.032 9 2.110 10 2.176 - 1 12 15 20 11 2.234 2.285 2.409 2.557
#1 A irreversible isothermal gas-phase isomerization reaction is given as: AB. This reaction is conducted in a 400L batch reactor and 100 mol of A (NAD = 100 mol) is charged into this reactor. The rate of reaction is determined as a function of the conversion of reactant A and the results are given below. The temperature was constant at 500K and the total pressure was constant at 830 kPa. The entering number of moles of species A is 100 mol. Calculate the time necessary to achieve 80% conversion. 0 0.1 0.2 0.4 -TA (mol/m³.s) 0.45 0.37 0.3 0.195 0.6 0.113 0.7 0.079 0.8 0.05
#3 A irreversible isothermal liquid-phase reaction is given as: A → B is conducted in continuous flow systems. The rate of reaction is determined as a function of the conversion of reactant A and the results are given below. The temperature was constant at 500K. The entering molar flow rate of A is 0.4 mol/min. a) If this reaction is conducted in two CSTRS in series. Calculate the required reactor volume of each CSTRS if conversion X₁ = 0.4 and conversion X2 = 0.8. b) If this reaction is conducted in two PFRS in series. Calculate the required reactor volume of each PFRS if conversion X₁ = 0.4 and conversion X2 = 0.8. c) If this reaction is conducted in a PFR followed by a CSTR. Calculate the required reactor volume of PFR if conversion X₁ = 0.4 and of CSTR if conversion X2 = 0.8. X -A (mol/L.min) 0 0.1 0.2 0.4 0.6 0.7 0.8 0.45 0.37 0.3 0.195 0.113 0.079 0.05
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