Explanation Given Info: The force applied by the athlete on the ground to support weight is 0.6 kN and the acceleration due to gravity is 9.80 m / s 2 . Write the formula to calculate the mass of the athlete. m = F g m is the mass of the athlete F is the force exerted by the athlete on the ground g is the acceleration due to gravity Substitute 0.6 kN for F and 9.80 m / s 2 for g to calculate m . m = 0.6 kN ( 1000 N 1 kN ) 9.80 m / s 2 = 600 N 9.80 m / s 2 = 61.2 kg Thus the athlete use the whole force except 0.6 kN , which is used for balancing athlete weight on the ground. Now redraw the graph from t = 0.0 s to t = 1.0 s . From the graph, the area under the graph would result to the total impulse. The base of the small triangle is 0.50 s , height of the small triangle is 0.1 kN , the base of the large triangle is 0.50 s , the height of the large triangle is 0.3 kN , the length of the rectangle is 0.50 s and breadth of the rectangle is 0.1 kN . Write the formula to calculate the impulse. I = 1 2 b h + 1 2 b ′ h ′ + l d I is the impulse b is the base of the small triangle h is the height of the small triangle b ′ is the base of the large triangle h ′ is the height of the large triangle l is the length of the rectangle d is the breadth of the rectangle Substitute 0.50 s for b , 0.1 kN for h , 0.50 s for b ′ , 0.3 kN for h ′ , 0.50 s for l and 0.1 kN for d to calculate I . I = 1 2 ( 0.50 s ) 0.1 kN ( 1000 N 1 kN ) + 1 2 ( 0.50 s ) 0

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ISBN: 9781285737027

Author: Raymond A. Serway, Chris Vuille

Publisher: Cengage Learning

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Chapter 6, Problem 68AP

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The magnitude of how high athlete jumps.

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Chapter 6, Problem 67AP

Chapter 6, Problem 69AP

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The magnitude of how high athlete jumps.

Solution Summary: The author calculates the magnitude of the athlete's height by subtracting the force exerted on the ground and the acceleration due to gravity.

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