Modern Database Management
13th Edition
ISBN: 9780134773650
Author: Hoffer
Publisher: PEARSON
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Chapter 6, Problem 6.77PAE
Program Plan Intro
Rewriting the query after identification of the special set of standard prices for which the query will not yield the required result.
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Write SQL codes according to the requirements given. Tables are imaginary, column names can be made up.
List the item ID, description, and category for each pair of items that are in the same category. (For example, one such pair would be item FS42 and item PF19, because the category for both items is FSH.)
List the invoice number and invoice date for each invoice created for the customer James Gonzalez.
Use a subquery to find the sales rep ID, first name, and last name of each sales rep who represents at least one customer with a credit limit of $500. List each sales rep only once in the results.
Using the output shown in Figure P7.12 as your guide, generate a list of customer purchases, including the subtotals for each of the invoice line numbers. The subtotal is a derived attribute calculated by multiplying LINE_UNITS by LINE_PRICE. Sort the output by customer code, invoice number, and product description. Be certain to use the column aliases as shown in the figure.
In the SQL Query do the following
Select clause: CUS_CODE, INV_NUMBER, P_DESCRIPT, LINE_UNITS AS “Units Bought”, LINE_PRICE as “Unit Price”, derived attribute Subtotal using the formula stated above
From: Join conditions between these tables INVOICE, LINE, PRODUCT
Where clause: You can put join conditions here as well if you do not want to put them in the from clause. There are many ways to write the query.
Order by clause: use the columns as stated in the problem description.
Write correlated and noncorrelated subqueries and understand when to use each.
Chapter 6 Solutions
Modern Database Management
Ch. 6 - Define each of the following terms: dynamic view...Ch. 6 - Match the following terms to the appropriate...Ch. 6 - Prob. 6.3RQCh. 6 - Prob. 6.4RQCh. 6 - Prob. 6.5RQCh. 6 - Explain the relationship between EXISTS and...Ch. 6 - Prob. 6.7RQCh. 6 - Under what conditions can a UNION clause be used?Ch. 6 - Prob. 6.9RQCh. 6 - Explain why it is necessary to limit the kinds of...
Ch. 6 - Describe a set of circumstances for which using a...Ch. 6 - Prob. 6.12RQCh. 6 - Prob. 6.13RQCh. 6 - Prob. 6.14RQCh. 6 - Prob. 6.15RQCh. 6 - Prob. 6.16RQCh. 6 - Prob. 6.17RQCh. 6 - Prob. 6.18RQCh. 6 - Prob. 6.19RQCh. 6 - List for advantages of SQL-invoked routines.Ch. 6 - Prob. 6.21RQCh. 6 - Prob. 6.22RQCh. 6 - Prob. 6.23RQCh. 6 - This chapter discusses the data dictionary views...Ch. 6 - Write an SQL query to answer the following...Ch. 6 - Write SQL retrieval commands for each of the...Ch. 6 - Write an SQL query to answer the following...Ch. 6 - Write SQL queries to answer the following...Ch. 6 - Write SQL queries to answer the following...Ch. 6 - Write an SQL query to answer the following...Ch. 6 - Prob. 6.31PAECh. 6 - Prob. 6.32PAECh. 6 - Prob. 6.33PAECh. 6 - What do you need to do if a tutor signs up and...Ch. 6 - Prob. 6.35PAECh. 6 - Write the SQL query to find any tutors who have...Ch. 6 - Prob. 6.37PAECh. 6 - Write an SQL query to determine the total number...Ch. 6 - Prob. 6.39PAECh. 6 - Prob. 6.40PAECh. 6 - Prob. 6.41PAECh. 6 - Prob. 6.42PAECh. 6 - Prob. 6.43PAECh. 6 - Which tutor needs to be reminded to tum in...Ch. 6 - Prob. 6.45PAECh. 6 - Write an SQL query to list all product line names...Ch. 6 - Modify to include only those product lines the...Ch. 6 - Prob. 6.48PAECh. 6 - Prob. 6.49PAECh. 6 - Write an SQL query to display the order number,...Ch. 6 - Prob. 6.51PAECh. 6 - Prob. 6.52PAECh. 6 - Prob. 6.53PAECh. 6 - Prob. 6.54PAECh. 6 - Prob. 6.55PAECh. 6 - Prob. 6.56PAECh. 6 - Prob. 6.57PAECh. 6 - Prob. 6.58PAECh. 6 - Write an SQL query to list each customer who...Ch. 6 - Prob. 6.60PAECh. 6 - Modify Problem and Exercise 6-60 so that the list...Ch. 6 - Prob. 6.62PAECh. 6 - Prob. 6.63PAECh. 6 - Prob. 6.64PAECh. 6 - Prob. 6.65PAECh. 6 - Prob. 6.66PAECh. 6 - Prob. 6.67PAECh. 6 - Prob. 6.68PAECh. 6 - Prob. 6.69PAECh. 6 - Prob. 6.70PAECh. 6 - Prob. 6.71PAECh. 6 - Rewrite your answer to Problem and Exercise 6-71...Ch. 6 - Display the customer ID, name, and order ID for...Ch. 6 - Prob. 6.74PAECh. 6 - Prob. 6.75PAECh. 6 - Prob. 6.76PAECh. 6 - Prob. 6.77PAECh. 6 - Prob. 6.78PAECh. 6 - Prob. 6.79PAECh. 6 - Write an SQL query to list the order number,...Ch. 6 - Prob. 6.81PAECh. 6 - Prob. 6.82PAECh. 6 - Prob. 6.83PAECh. 6 - Prob. 6.84PAECh. 6 - Prob. 6.85PAE
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- Delete the OWNER_INDEX 3 index from the OWNER table.arrow_forwardModify the query in Problem 13 to include the number of individual product purchases made by each customer. (In other words, if the customer’s invoice is based on three products, one per LINE_NUMBER, you count three product purchases. Note that in the original invoice data, customer 10011 generated three invoices, which contained a total of six lines, each representing a product purchase.) Your output values must match those shown in Figure P7.14, sorted by customer code.arrow_forwardUsing the relations in the appendix, write the following queries in SQL:i. Display a list of all instructors, showing each instructor’s ID and the number of sections taught. Your query should use an outer join, and should not use sub-queries.ii. Write the same query as in part a, but using a scalar subquery and not using outer join.iii. Display the list of all course sections offered in spring 2018, along with the ID and name of each instructor teaching the section. If a section has more than one instructor, that section should appear as many times in the result as it has instructors. If a section does not have any instructor, it should still appear in the result with the instructor name set to “—”.iv. Display the list of all departments, with the total number of instructors in each department, without using sub-queries. Make sure to show departments that have no instructors, and list those departments with an instructor count of zero.arrow_forward
- Write a SQL query. List names of all employees who have sold to customer Rachel Patterson (Note: You can only use the information given in the question, i.e. you cannot first look up Rachel Patterson’s Customer ID and use that ID in your query).arrow_forwardI NEED HELP WITH THIS QUESTION FOR MY DATABASE MANAGEMENT CLASS FOR SQL DEVELOPER In reporting total_sale by each REP including those who made no sale, which Table joins should be left join. And how to show zero in your report instead of null for reps with no sale.arrow_forwardCreate a Queries using the Design View.arrow_forward
- Considering Vaccination Database, write queries to: Display the Subject CNIC, Name, Contact, Dose1 Center, and Dose2 Center as shown below: CNIC Name Contact Dose1 Center Dose2 Center 22401-6645321-1 Nasir 3409991112 Lachi Kohat 2 14301-6045321-5 Shahab 3409991112 kohat 3 Dara The subjects who have been vaccinated different types in Dose1 and Dose2. For instance, subjects who were vaccinated ‘Sinovac’ in the first dose, while Pfizer in the second dose.How many Viles of each type have been consumed so far. How many subjects are vaccinated from expired viles. Suggest the name of Incharge for the best performance award based on the highest number of subjects vaccinated on a single dayarrow_forwardWithout re-creating the table write one sql statement to answer this question. Change the definition of Riverview_customer to include the customer type, but name this column custtype. Put a restriction on the table to ensure that the customer types will include values of O, L and N. Name this restriction valid_custtypesarrow_forwardCould you do typing the query here please?arrow_forward
- Given the table PRODUCT(ProductID, ProductName, ProductClass, ProductWeight, ProductStyle, ProductColor, ProductPrice). Note: ProductWeight and ProductPrice are numeric fields, and the other attributes are character fields, i.e., store text. Write a SQL query to retrieve the ID and name of the products whose ProductColor contains the word "green" and whose price is at most $30arrow_forwardWhat are some of the uses you might have for correlated subqueries?arrow_forwardFor every order that has been received, display the order ID, the total dollar amount owed on that order (you’ll have to calculate this total from attributes in one or more tables; label this result TotalDue), and the amount received in payments on that order (assume that there is only one payment made on each order). To make this query a little simpler, you don’t have to include those orders for which no payment has yet been received. List the results in decreasing order of the difference between total due and amount paid.arrow_forward
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