Modern Database Management
13th Edition
ISBN: 9780134773650
Author: Hoffer
Publisher: PEARSON
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Chapter 6, Problem 6.70PAE
Program Plan Intro
SQL query showing EmployeeName and EmployeeID for those employees who do not possess skill router. Also, show how it is constructed using Venn diagram
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Task 18: List the item ID, description, unit price, and category for each item that has a unit price greater than the unit price of every item in category CAT. Use the ALLoperator in your query.
Task 20: Repeat Task 18 using the ANY operator.
*Both are needed answered but ideally task 20 needs to be done, task 18 is here for task 20
For each order, list the order ID, customer ID, order date, and most recent date among all orders. Show how you constructed this query using a Venn diagram.
The team wants to track potential list of users who may have forgotten their items on the cars. Therefore, you need to return USER_FIRST_NAME, USER_LAST_NAME, TRAVEL_START_TIME, TRAVEL_END_TIME information from the USERS and TRAVELS tables connected inside a JOIN statement by the USING function and USER_ID field
Chapter 6 Solutions
Modern Database Management
Ch. 6 - Define each of the following terms: dynamic view...Ch. 6 - Match the following terms to the appropriate...Ch. 6 - Prob. 6.3RQCh. 6 - Prob. 6.4RQCh. 6 - Prob. 6.5RQCh. 6 - Explain the relationship between EXISTS and...Ch. 6 - Prob. 6.7RQCh. 6 - Under what conditions can a UNION clause be used?Ch. 6 - Prob. 6.9RQCh. 6 - Explain why it is necessary to limit the kinds of...
Ch. 6 - Describe a set of circumstances for which using a...Ch. 6 - Prob. 6.12RQCh. 6 - Prob. 6.13RQCh. 6 - Prob. 6.14RQCh. 6 - Prob. 6.15RQCh. 6 - Prob. 6.16RQCh. 6 - Prob. 6.17RQCh. 6 - Prob. 6.18RQCh. 6 - Prob. 6.19RQCh. 6 - List for advantages of SQL-invoked routines.Ch. 6 - Prob. 6.21RQCh. 6 - Prob. 6.22RQCh. 6 - Prob. 6.23RQCh. 6 - This chapter discusses the data dictionary views...Ch. 6 - Write an SQL query to answer the following...Ch. 6 - Write SQL retrieval commands for each of the...Ch. 6 - Write an SQL query to answer the following...Ch. 6 - Write SQL queries to answer the following...Ch. 6 - Write SQL queries to answer the following...Ch. 6 - Write an SQL query to answer the following...Ch. 6 - Prob. 6.31PAECh. 6 - Prob. 6.32PAECh. 6 - Prob. 6.33PAECh. 6 - What do you need to do if a tutor signs up and...Ch. 6 - Prob. 6.35PAECh. 6 - Write the SQL query to find any tutors who have...Ch. 6 - Prob. 6.37PAECh. 6 - Write an SQL query to determine the total number...Ch. 6 - Prob. 6.39PAECh. 6 - Prob. 6.40PAECh. 6 - Prob. 6.41PAECh. 6 - Prob. 6.42PAECh. 6 - Prob. 6.43PAECh. 6 - Which tutor needs to be reminded to tum in...Ch. 6 - Prob. 6.45PAECh. 6 - Write an SQL query to list all product line names...Ch. 6 - Modify to include only those product lines the...Ch. 6 - Prob. 6.48PAECh. 6 - Prob. 6.49PAECh. 6 - Write an SQL query to display the order number,...Ch. 6 - Prob. 6.51PAECh. 6 - Prob. 6.52PAECh. 6 - Prob. 6.53PAECh. 6 - Prob. 6.54PAECh. 6 - Prob. 6.55PAECh. 6 - Prob. 6.56PAECh. 6 - Prob. 6.57PAECh. 6 - Prob. 6.58PAECh. 6 - Write an SQL query to list each customer who...Ch. 6 - Prob. 6.60PAECh. 6 - Modify Problem and Exercise 6-60 so that the list...Ch. 6 - Prob. 6.62PAECh. 6 - Prob. 6.63PAECh. 6 - Prob. 6.64PAECh. 6 - Prob. 6.65PAECh. 6 - Prob. 6.66PAECh. 6 - Prob. 6.67PAECh. 6 - Prob. 6.68PAECh. 6 - Prob. 6.69PAECh. 6 - Prob. 6.70PAECh. 6 - Prob. 6.71PAECh. 6 - Rewrite your answer to Problem and Exercise 6-71...Ch. 6 - Display the customer ID, name, and order ID for...Ch. 6 - Prob. 6.74PAECh. 6 - Prob. 6.75PAECh. 6 - Prob. 6.76PAECh. 6 - Prob. 6.77PAECh. 6 - Prob. 6.78PAECh. 6 - Prob. 6.79PAECh. 6 - Write an SQL query to list the order number,...Ch. 6 - Prob. 6.81PAECh. 6 - Prob. 6.82PAECh. 6 - Prob. 6.83PAECh. 6 - Prob. 6.84PAECh. 6 - Prob. 6.85PAE
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- Question 6 List classroom ID, building name, class ID and class description. Use a LEFT JOIN to list all the classrooms in the BSU_Classrooms table and show matching Class ID and class description from the BSU_Class table. Sort results in descending order by classroom ID. Paste the SQL code here: Paste the resulting table here:arrow_forwardJOIN TABLES One row in the PAT_ENC table represents one patient encounter. One row in the ORDER MED table represents one medication order. One patient encounter can have many medication orders but one medication order can only have one patient encounter. In other words, the cardinality of this PAT_ENC to ORDER_MED relationship is one-to- many. You start a query with PAT_ENC. You then add ORDER_MED using an inner join. What is true about the granularity of the result set before and after adding the ORDER_MED table? SELECT ONE OF THE FOLLOWING A. The granularity stays at one row per patient encounter. B. The granularity stays at one row per medication order. C. The granularity changes from one row per patient encounter to one row per medication order on an encounter. D. The granularity changes from one row per medication order to one row per patient encounter.arrow_forwardcode of create table and insert table only pleasearrow_forward
- Animal animal_id name adopter_id Adopter adopter_id name Given the above data for an adoption agency, what does the result set for the following query represent? SELECT adopter.name, animal.name FROM Animal CROSS JOIN Adopter; It represents every single Animal in the animal table regardless of whether they have been adopted or not. O It represents every single animal matches with every single adopter. It represents each animal, with the name of their adopter if that has been specified via a Foreign Key. QI 77°F Sunny Imml Warrow_forwardShow a list of employee id, names, department, years and job of any employee in the staff table who makes a total amount more than their manager or has more years of service than their manager. Make sure to include both salary and commission when calculating the total amount someone makes. Exclude staff in department 10 from the query. Order the results by department then namearrow_forwardCreate a query to show the Technician Number, Last Name, First Name, Client Number,and Client Name for clients whose technician number is 23 (use Boolean variables).Save your queryarrow_forward
- Why the following statement is erroneous? SELECT dept_name, ID, avg (salary) FROM instructor GROUP BY dept_name; a) Dept_id should not be used in group by clause b) Group by clause is not valid in this query c) Avg(salary) should not be selected d) Nonearrow_forwardWhat is missing from the join statement? SELECT Employee Name, Salary FROM Employee, Department WHERE Salary > 50000;arrow_forwardRewrite the following query using a join statement (no subqueries). (0.5) SELECT productid, productname, productprice FROM product WHERE productid IN (SELECT productid FROM soldvia GROUP BY productid HAVING SUM(noofitems) > 3);arrow_forward
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