Concept explainers
A.
Explanation of Solution
“Yes”, SQL server supports both locking such as optimistic and pessimistic.
Reason:
The SQL server supports the optimistic and pessimistic locks.
Optimistic lock:
- Multiple users can update the data and it gets lock after the transaction has been processed in optimistic lock. It can be used for web applications.
- There is no conflict occur during transaction. If conflict occurs then it can be repeated until no conflict.
- There is no need to lock the
database resources and it prevents database from deadlocks. - The disadvantage is that it allows the applications from selecting and modifying the same data...
B.
Explanation of Solution
Transaction Isolation Level:
The transaction isolation level gives the measure of the extent to which transaction isolation succeeds.
- This process is defined by the presence or the absence of the phenomena such as dirty read, nonrepeatable reads, and phantom read.
- These problems occur when we read data from the database.
There are four levels of transactions. They are,
- Read uncommitted isolation level
- Read committed isolation level
- Repeatable reads isolation level
- Serializable isolation level
Read uncommitted isolation level:
Read uncommitted isolation level is the lowest isolation level which allows dirty reads, nonrepeatable reads, and phantom reads.
- It makes the transaction to read any data currently on a data page irrespective of the data has been committed.
- The uncommitted read isolation level applies to read-only operations like SELECT, SELECT INTO, and FETCH.
- The uncommitted read should not be applied for the cases where the answer must be accurate.
- The uncommitted read does affect other transactions.
Read committed Isolation level:
Read committed Isolation level allows nonrepeatable reads and phantom reads but it prevents dirty read...
C.
Explanation of Solution
Cursor:
The term cursor is used to retrieve the information in row by row manner. If the records stored in the database table, which needs to be updated one row at a time is carried over by cursor.
- It plays the major role for fetching a required row from the table in the database which holds numerous records.
- Cursors are defined using SELECT statement.
- It points the set of rows which is resulted from an SQL SELECT statement.
- In general the cursor is placed in the first or last row.
- It influences the performance of the SQL Server as it uses the SQL server instances memory, decrease network bandwidth, and reduction in concurrency.
- It’s recommended to avoid the use of cursor and the cursor can be replaced with WHILE loop, temporary tables, and sub queries.
- The types of cursor are listed below:
- Forward-only cursor
- Static cursor
- Dynamic cursor
- Keyset cursor
Forward-only cursor:
Forward-only cursor is used for fastest retrieval of data from the database. It is the fastest cursor among all the cursors but with the drawback it does not support backward scrolling.
- Data deletion, updating the data can be done using the Forward-Only cursor.
- It is sensitive as any changes made in the database will affect the original data source...
D.
Explanation of Solution
Difference between Security model for SQL server and figure 6-16:
Note: Refer Figure 6-16 in textbook: “A model of DBMS security”
Security model for SQL server | Security model for database Management system |
It provides the security architecture to permit the database developer to make secure database application and counter threats. |
It provides the |
It contains the hierarchical set of entities with server. Each and every server contains multiple databases, and each and every database contains set of securable objects... |
E.
Explanation of Solution
Types of SQL server backup:
There are different types of SQL server backups. They are,
- Full backup
- Differential backup
- Transaction log backup
- Database file and Filegroup backups
Full backup:
The full backup in SQL server is simple type of backup which does not depends on recovery model.
- It backs up the any type of activity during the backup.
- It backs up any type of uncommitted transactions in transaction log file.
Differential backup:
The differential backup helps to reduce the time for restoring the modified database.
- It backs up the portion of database that have modified since final full database backup.
- It backs up any type of activity during differential backup and also any type of uncommitted transactions in transaction log file...
F.
Explanation of Solution
SQL server recovery models:
There are three different types of recovery models in SQL server. They are,
- Simple
- Full
- Bulk-logged
Simple:
Simple recovery model helps to maintains smallest quantity of information in transaction log.
- Simple recovery model restores the data from full or differential backups. It requires less administration power and easy to manage than full or bulk-logged model.
- It expense high data loss when data file damages occurs.
- The benefits allows the high-performance copy operation.
- The drawback of the simple model is changes because database or differential backup must need to be rebuild...
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EBK DATABASE CONCEPTS
- Consider the data path below for a single cycle 32-bits MIPS processor Assume that we are executing the following instruction lw $11, 48($10) What is the value of the element pointed by arrow number 1 by in hexadecimal or binary? Note that the PC and the content of registers $10 and $t1 are found in bottom left of the figure below Data Memory Select one a. Ob 01001' O b. 0x000016F0 Oc 06'1000' Od 06/00000 Oe. None of the options Of. 0x000016F4 AM RegDe ALU Address Content 0x000016EC 0x0000ABOD 0x000016F0 0x00A01245 0x000016F4 0x00001A42 0x000171C Ox0008124F 0x0001720 Ox00021345 0x0001724 0x000067AB ALU AL 0x0001734 Ox0000AB35 0x0001738 0x0000FA72 0x000174C 0x0000ABOC Register File and PC Sto Ox000016F0 $t1 = 0x000016F4 PC 0x000014BA0 (Before executing LW)arrow_forwardConsider the data path below for a single cycle 32-bits MIPS processor Assume that we are executing the following instruction ADD $3, $50, $2 What is the value of the element pointed by arrow number 1 by in hexadecimal? Note that the PC and the content of registers $10 and $t1 are found in bottom left of the figure below Select one Oa. OxFFFFFF30 b. None of the options Oc 0xFFFF9820 Od 0x00009620 Oe. 0xFFFFFF48 Address 0x000016EC Content 0x0000ABOD Data Memory 0x000016FO 0x00401245 0x000016F4 0x00001A42 0x0001710 0x0008124F 0x0001720 0x00021345 0x0001724 0x000067AB 11 81 0x0001734 0x0000AB35 0x0001738 0x0000FA72 0x0000ABOC Register File and PC 0x000174C $50 = 0x0000AF00 $12 = 0x000000BA $x3 = 0x00000001 PC-0x000FAC04 (Before executing ADD)arrow_forwardConsider the data path below for a single cycle 32-bits MIPS processor Assume that we are executing the following instruction ADD $3, $50, $s2 What is the value of the element pointed by arrow number 1 by in hexadecimal? Note that the PC and the content of registers are found in bottom left of the figure below Select one a. Ox000FACOB Ob. 0x000F4428 Oc None of the options Od 0x00120C84 O e. 0x000FAC04 Address Ox000016EC Data Memory 0x000016F0 Content 0x0000ABOD C0001245 Ox000016F4 0x00001A42 0x000171C C0008124F 0x0001720 0x00021345 0x0001724 0x000067AB 0x0001734 0x0000AB35 0x0001738 0x0000FA72 0x000174C ОКООООАВОС Register File and PC $50-0x0000AF00 Ss2=0x000000BA Ss3 0x00000001 PC-Ox000FAC04 (Before executing ADD)arrow_forward
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