Chapter 6, Problem 6.40QP

Interpretation Introduction

Interpretation: The atmospheric pressure on Uranus is given to exceed ${10}^8\text{Pa}$ and acceleration due to gravity is given to be similar to that on Earth. The mass of the atmosphere on Uranus is to be calculated.

Concept introduction: The ratio of force per unit area of an object is defined as pressure. The formula to calculate pressure is,

$P=\frac{F}{A}$

Where,

• $P$ represents the pressure.
• $F$ represents the force.
• $A$ represents the surface area.

Force is defined as product of mass and the acceleration caused by the gravitational force. The formula to calculate force is,

$F=ma$

Where,

• $F$ represents the force.
• $m$ represents the mass.
• $a$ represents the acceleration.

To determine: The mass of the atmosphere on Uranus.