Chapter 6, Problem 6.130QP

Interpretation Introduction

Interpretation: The root-mean-square speed of $\text{Ne}$ at $2.00\text{atm}$ is half, twice or the same as root-mean-square speed of $\text{Ne}$ at $760\text{mm}\text{Hg}$ is to be determined.

Concept introduction: The root-mean-square speed is used to find out the single value of speed of the gas molecules that move in random directions having different speed and the formula is,

$u_{rms}=\sqrt{\frac{3\text{R}T}{M}}$

To determine: If the root-mean-square speed of $\text{Ne}$ at $2.00\text{atm}$ is half, twice or the same as root-mean-square speed of $\text{Ne}$ at $760\text{mm}\text{Hg}$.