Chapter 6, Problem 6.1NP

Interpretation Introduction

Interpretation : The value of $\Delta A_R^0\text{ and }\Delta G_R^0$ for the reaction ${\text{C}}_6{\text{H}}_6(l){\text{ + 15/2 O}}_2\left(g\right)\to {\text{ 6 CO}}_2(g){\text{ + 3 H}}_2\text{O(}l)$ at $298\text{ K}$ should be calculated from the combustion enthalpy of benzene and the entropies of reactants and products.

Concept Introduction :

The Gibbs free energy change can be calculated as follows:

  $\Delta G^0=\Delta H^0-T.\Delta S^0$

Here,

  $\begin{array}{l}\Delta G^0\text{ - Gibbs free energy change}\\ \Delta H^0\text{ - enthalpy change}\\ T\text{ - temperature}\\ \Delta S^0\text{ - entropy change}\end{array}$

Also, the Helmholtz free energy change can be calculated as follows:

  $\Delta A^0=\Delta U^0-T.\Delta S^0$

Here,

  $\begin{array}{l}\Delta A^0\text{ - Helmholtz free energy change}\\ \Delta U^0\text{ - internal energy change}\end{array}$