Chapter 6, Problem 6.16P

(a)

Interpretation Introduction

Interpretation:

The chemical formula for ruthenium (III) sulphide has to be written.

Concept Introduction:

1. 1) The chemical formula of binary compound from a pair of its constituent ion has to be written.
2. 2) The coefficients of the ions with the magnitude of the charge on each of the ions have to be crossed multiplied.  This is done to neutralize charge on the binary compound.
3. 3) The oxidation state of the metal is written in roman numbers in the brackets

(b)

Interpretation Introduction

Interpretation:

The chemical formula for scandium fluoride has to be written.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The chemical formula for osmium (VIII) oxide has to be written.

Concept Introduction:

Refer to part (a).

(d)

Interpretation Introduction

Interpretation:

The chemical formula for manganese (II) sulphide has to be written.

Concept Introduction:

Refer to part (a).

(e)

Interpretation Introduction

Interpretation:

The chemical formula for platinum (IV) chloride has to be written.

Concept Introduction:

Refer to part (a).