Explanation The combustion reaction of octane is written as, C 8 H 18(l) + 25 2 O 2(g) → 8CO 2(g) +9H 2 O ( l ) ΔH°=-5500 kJ/mole The density of octane is 0 .70 g/ml . Assume for twenty gallon gas tank, the energy content is calculated as, Energy = 20 gal× 3 .78 L 1 gal × 1000 ml 1 L × 0 .70 g C 8 H 18 1 ml × 1 mole C 8 H 18 114 .22 gC 8 H 18 × 5500 kJ 1 mole C 8 H 18 = 2

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Author: Chang

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Chapter 6, Problem 6.154QP

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The pressure at which hydrogen gas need to be kept for the tank to contain an equivalent amount of chemical energy as tank of gasoline has to be given.

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Chapter 6, Problem 6.153QP

Chapter 6, Problem 6.155QP

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Chapter 6 Solutions

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The pressure at which hydrogen gas need to be kept for the tank to contain an equivalent amount of chemical energy as tank of gasoline has to be given.

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Chapter 6 Solutions

Interpretation:

The pressure at which hydrogen gas need to be kept for the tank to contain an equivalent amount of chemical energy as tank of gasoline has to be given.