
CHEMISTRY (LL) W/CNCT >BI<
13th Edition
ISBN: 9781260572384
Author: Chang
Publisher: MCG
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Chapter 6, Problem 6.110QP
Interpretation Introduction
Interpretation:
The change in enthalpy of 6.6×105 g of SO2 removed from the process has to be calculated.
Concept Introduction:
The change in enthalpy that is associated with the formation of one mole of a substance from its related elements being in standard state is called standard enthalpy of formation (ΔHf°). The standard enthalpy of formation is used to determine the standard enthalpies of compound and element.
The standard enthalpy of reaction is the enthalpy of reaction that takes place under standard conditions.
The equation for determining the standard enthalpies of compound and element can be given by,
ΔH°reaction=∑nΔH°f(products)-∑mΔH°f(reactants)
To calculate: The change in enthalpy of 6.6×105 g of SO2
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MISSED THIS? Read Section 19.9 (Pages 878-881); Watch IWE 19.10
Consider the following reaction:
CH3OH(g)
CO(g) + 2H2(g)
(Note that AG,CH3OH(g) = -162.3 kJ/mol and AG,co(g)=-137.2 kJ/mol.)
Part A
Calculate AG for this reaction at 25 °C under the following conditions:
PCH₂OH
Pco
PH2
0.815 atm
=
0.140 atm
0.170 atm
Express your answer in kilojoules to three significant figures.
Ο ΑΣΦ
AG = -150
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kJ
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Calculate the free energy change under nonstandard conditions (AGrxn) by using the following relationship:
AGrxn = AGrxn + RTInQ,
AGxn+RTInQ,
where AGxn is the standard free energy change, R is the ideal gas constant, T is the temperature in kelvins, a
is the reaction quotient.
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Chapter 6 Solutions
CHEMISTRY (LL) W/CNCT >BI<
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