Chapter 6, Problem 6.14P

(a)

Interpretation Introduction

Interpretation:

The energy absorbed from decomposition of ${\text{CaCO}}_3$ in $\text{J}$ is to be calculated.

Concept introduction:

Internal energy of a process is the summation of the kinetic energy and potential energy associated with the process. In case of reaction, the change in internal energy $\left(\Delta E\right)$ is the difference of the energy of the product and reactant.

The expression to convert $\text{kJ}$ into $\text{J}$ is:

$\text{1}\text{kJ}=1000\text{J}$

(b)

Interpretation Introduction

Interpretation:

The energy absorbed from decomposition of ${\text{CaCO}}_3$ in $\text{cal}$ is to be calculated.

Concept introduction:

Internal energy of a process is the summation of the kinetic energy and potential energy associated with the process. In case of reaction, the change in internal energy $\left(\Delta E\right)$ is the difference of the energy of the product and reactant.

The expression to convert $\text{cal}$ into $\text{J}$ is:

$\text{1}\text{cal}=4.184\text{J}$

(c)

Interpretation Introduction

The energy absorbed from decomposition of ${\text{CaCO}}_3$ in $\text{Btu}$ is to be calculated.

Concept introduction:

Internal energy of a process is the summation of the kinetic energy and potential energy associated with the process. In case of reaction, the change in internal energy $\left(\Delta E\right)$ is the difference of the energy of the product and reactant.

The expression to convert $\text{Btu}$ into $\text{kJ}$ is:

$\text{1}\text{Btu}=1055\text{J}$