Chapter 6, Problem 6.111QP

Interpretation Introduction

Interpretation: The percent decrease in pressure of a sealed reaction vessel during the reaction between $\text{3}\text{.60}\times {\text{10}}^{\text{3}}\text{mol}$ of ${\text{H}}_{\text{2}}$ and $\text{1}\text{.20}\times {\text{10}}^{\text{3}}\text{mol}$ of ${\text{N}}_{\text{2}}$ if half of the ${\text{N}}_{\text{2}}$ consumed is to be calculated.

Concept introduction: The reaction between nitrogen and hydrogen involves the formation of ammonia. When one mole of nitrogen reacts with three moles of hydrogen then it produces 2 moles of ammonia. The balanced equation is given below,

${\text{N}}_{\text{2}}\left(\text{g}\right)+{\text{3H}}_{\text{2}}\left(\text{g}\right)\to {\text{2NH}}_{\text{3}}\left(\text{g}\right)$

From the ideal gas equation, at constant temperature and volume, Pressure is directly proportional to the number of moles,

$P\propto n$

To determine: The percent decrease in pressure of a sealed reaction vessel during the reaction between $\text{3}\text{.60}\times {\text{10}}^{\text{3}}\text{mol}$ of ${\text{H}}_{\text{2}}$ and $\text{1}\text{.20}\times {\text{10}}^{\text{3}}\text{mol}$ of ${\text{N}}_{\text{2}}$ if half of ${\text{N}}_{\text{2}}$ consumes.