Chapter 6, Problem 6.101MP

(a)

Interpretation Introduction

To Determine:

The ionization energy of rubidium atoms in kilojoules per mole if light with $\lambda =58.4nm$ produces electrons with a velocity of $2.450\times {10}^{6}m/s$. (The mass of an electron is $9.109\times {10}^{-31}kg$ )

(b)

Interpretation Introduction

To Determine:

The ionization energy of potassium in kilojoules per mole if the light with $\lambda =142nm$ produces electrons with a velocity of $2.450\times {10}^{6}m/s$.