In recent years, scientists have discovered hundreds of planets orbiting other stars. Some of these planets are in orbits that are similar to that of earth, which orbits the sun ( M sun = 1.99 × 10 30 kg) at a distance of 1.50 × 10 11 m, called 1 astronomical unit (1 au). Others have extreme orbits that are much different from anything in our solar system. Problems 47–49 relate to some of these planets that follow circular orbits around other stars. 49. Kepler-42c orbits at a very close 0.0058 au from a small star with a mass that is 0.13 that of the sun. How long is a “year” on this world?
In recent years, scientists have discovered hundreds of planets orbiting other stars. Some of these planets are in orbits that are similar to that of earth, which orbits the sun ( M sun = 1.99 × 10 30 kg) at a distance of 1.50 × 10 11 m, called 1 astronomical unit (1 au). Others have extreme orbits that are much different from anything in our solar system. Problems 47–49 relate to some of these planets that follow circular orbits around other stars. 49. Kepler-42c orbits at a very close 0.0058 au from a small star with a mass that is 0.13 that of the sun. How long is a “year” on this world?
In recent years, scientists have discovered hundreds of planets orbiting other stars. Some of these planets are in orbits that are similar to that of earth, which orbits the sun (Msun = 1.99 × 1030 kg) at a distance of 1.50 × 1011 m, called 1 astronomical unit (1 au). Others have extreme orbits that are much different from anything in our solar system. Problems 47–49 relate to some of these planets that follow circular orbits around other stars.
49. Kepler-42c orbits at a very close 0.0058 au from a small star with a mass that is 0.13 that of the sun. How long is a “year” on this world?
SARET CRKS AUTOWAY
12. A stone is dropped from the top of a cliff. It is seen to hit the ground below
after 3.55 s. How high is the cliff?
13. A ball is dropped from rest at the top of a building that is 320 m tall. Assuming
no air resistance, what is the speed of the ball just before it strikes the ground?
14. Estimate (a) how long it took King Kong to fall straight down from the top
of the Empire State Building (280m high), and (b) his velocity just before
"landing".
Useful equations
For Constant Velocity:
V =>
D
X = V₁t + Xo
For Constant Acceleration:
Vr = V + at
X = Xo+Vot +
v=V+2a(X-Xo)
\prom = V +V
V velocity
t = time
D Distance
X = Final Position
Xo Initial Position
V = Final Velocity
Vo Initial Velocity
a = acceleration
For free fall
Yf
= Final Position
Yo Initial Position
g = 9.80
m
$2
For free fall:
V = V + gt
Y=Yo+Vo t +
+gt
V,² = V₁²+2g (Y-Yo)
V+Vo
Vprom=
2
6
Solve the problems
Chapter 6 Solutions
College Physics: A Strategic Approach (3rd Edition)
Genetic Analysis: An Integrated Approach (3rd Edition)
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