Explanation Given data: Speed of satellite A in orbiting Planet is 10 , 000 m s . Times Planet B is massive than Planet A is 2. Times the distance of Planet B from the center of the of the planet than Planet A is 2. Formula used: Write the expression for speed of the satellite. v = G M r (1) Here, v is the velocity, G is the gravitational constant with value 6.67 × 10 − 11 N ⋅ m 2 kg 2 , M is the mass of object, and r is the radius. Modify equation (1) for Planet A as follows. v A = G M r A (2) For Planet B, v B = G M r B (3) Dividing equation (3) and (2), v B v A = r A

College Physics: A Strategic Approach (3rd Edition)

3rd Edition

ISBN: 9780321879721

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Chapter 6, Problem 43P

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The speed of satellite B.

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Chapter 6, Problem 42P

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Chapter 6 Solutions

College Physics: A Strategic Approach (3rd Edition)

Ch. 6 - A cyclist goes around a level, circular track at...Ch. 6 - In uniform circular motion, which of the following...Ch. 6 - A particle moving along a straight line can have...Ch. 6 - Would having four-wheel drive on a car make it...Ch. 6 - Large birds like pheasants often walk short...Ch. 6 - When you drive fast on the highway with muddy...Ch. 6 - A ball on a string moves in a vertical circle as...Ch. 6 - Give an everyday example of circular motion for...Ch. 6 - Give an everyday example of circular motion for...Ch. 6 - Its been proposed that future space stations...

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The speed of satellite B.

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The speed of satellite B.

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Chapter 6 Solutions