Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
8th Edition
ISBN: 9780134421377
Author: Charles H Corwin
Publisher: PEARSON
Question
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Chapter 6, Problem 49E
Interpretation Introduction

(a)

Interpretation:

The formula for the binary molecular compound dinitrogen trioxide is to be stated.

Concept introduction:

A binary molecular compound is composed of two nonmetal elements. The simplest representative particle in a binary molecular compound is a molecule. Generally, the more nonmetallic element is written second in the chemical formula. The general order of the elements in compound which is prescribed by IUPAC is C,P,N,H,S,I,Br,Cl,O,F and the compounds are to be written according to the above order.

Expert Solution
Check Mark

Answer to Problem 49E

The formula for the binary molecular compound dinitrogen trioxide is N2O3.

Explanation of Solution

In the naming of binary molecular compound, IUPAC suggested that the first element in the compound to be named is followed by the second element bearing the suffix ide. It also suggested that the number of atoms of each element is indicated by Greek prefixes. In compound dinitrogen trioxide, the ratio is two nitrogen atoms to three oxygen atoms. The suffix ide is used for oxygen. Therefore, the formula for the compound dinitrogen trioxide is N2O3.

Conclusion

The formula for the binary molecular compound dinitrogen trioxide is N2O3.

Interpretation Introduction

(b)

Interpretation:

The formula for the binary molecular compound carbon tetrachloride is to be stated.

Concept introduction:

A binary molecular compound is composed of two nonmetal elements. The simplest representative particle in a binary molecular compound is a molecule. Generally, the more nonmetallic element is written second in the chemical formula. The general order of the elements in compound which is prescribed by IUPAC is C,P,N,H,S,I,Br,Cl,O,F and the compounds are to be written according to the above order.

Expert Solution
Check Mark

Answer to Problem 49E

The formula for the binary molecular compound carbon tetrachloride is CCl4.

Explanation of Solution

In the naming of binary molecular compound, IUPAC suggested that the first element in the compound to be named is followed by the second element bearing the suffix ide. It also suggested that the number of atoms of each element is indicated by Greek prefixes. In compound carbon tetrachloride, the ratio of atoms is one carbon atom to four chlorine atoms. The suffix ide is used for chlorine. Therefore, the formula for the compound carbon tetrachloride is CCl4.

Conclusion

The formula for the binary molecular compound carbon tetrachloride is CCl4.

Interpretation Introduction

(c)

Interpretation:

The formula for the binary molecular compound iodine monobromide is to be stated.

Concept introduction:

A binary molecular compound is composed of two nonmetal elements. The simplest representative particle in a binary molecular compound is a molecule. Generally, the more nonmetallic element is written second in the chemical formula. The general order of the elements in compound which is prescribed by IUPAC is C,P,N,H,S,I,Br,Cl,O,F and the compounds are to be written according to the above order.

Expert Solution
Check Mark

Answer to Problem 49E

The formula for binary molecular compound iodine monobromide is IBr.

Explanation of Solution

In the naming of binary molecular compound, IUPAC suggested that the first element in the compound to be named is followed by the second element bearing the suffix ide. It also suggested that the number of atoms of each element is indicated by Greek prefixes. In the compound iodine monobromide, the ratio of atoms is one iodine atom to one bromine atom. The suffix ide is used for bromine. Therefore, the formula for the compound iodine monobromide is IBr.

Conclusion

The formula for binary molecular compound iodine monobromide is IBr.

Interpretation Introduction

(d)

Interpretation:

The formula for the binary molecular compound dihydrogen sulfide is to be stated.

Concept introduction:

A binary molecular compound is composed of two nonmetal elements. The simplest representative particle in a binary molecular compound is a molecule. Generally, the more nonmetallic element is written second in the chemical formula. The general order of the elements in compound which is prescribed by IUPAC is C,P,N,H,S,I,Br,Cl,O,F and the compounds are to be written according to the above order.

Expert Solution
Check Mark

Answer to Problem 49E

The formula for binary molecular compound dihydrogen sulfide is H2S.

Explanation of Solution

In the naming of binary molecular compound, IUPAC suggested that the first element in the compound to be named is followed by the second element bearing the suffix ide. It also suggested that the number of atoms of each element is indicated by Greek prefixes. In compound dihydrogen sulfide, the ratio of atoms is two hydrogen atoms to one sulfur atom. The suffix ide is used for sulfur. Therefore, the formula for the compound carbon tetrachloride is CCl4.

Conclusion

The formula for binary molecular compound dihydrogen sulfide is H2S.

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Chapter 6 Solutions

Introductory Chemistry: Concepts and Critical Thinking (8th Edition)

Ch. 6 - Prob. 11CECh. 6 - Prob. 12CECh. 6 - Prob. 13CECh. 6 - Prob. 14CECh. 6 - Prob. 15CECh. 6 - Prob. 16CECh. 6 - Prob. 17CECh. 6 - Prob. 18CECh. 6 - Prob. 19CECh. 6 - Prob. 1KTCh. 6 - Prob. 2KTCh. 6 - Prob. 3KTCh. 6 - Prob. 4KTCh. 6 - Prob. 5KTCh. 6 - Prob. 6KTCh. 6 - Prob. 7KTCh. 6 - Prob. 8KTCh. 6 - Prob. 9KTCh. 6 - Prob. 10KTCh. 6 - Prob. 11KTCh. 6 - Prob. 12KTCh. 6 - Prob. 13KTCh. 6 - Prob. 14KTCh. 6 - Prob. 15KTCh. 6 - Prob. 16KTCh. 6 - Prob. 17KTCh. 6 - Prob. 1ECh. 6 - Prob. 2ECh. 6 - Prob. 3ECh. 6 - Prob. 4ECh. 6 - Prob. 5ECh. 6 - Prob. 6ECh. 6 - Prob. 7ECh. 6 - Prob. 8ECh. 6 - Prob. 9ECh. 6 - Prob. 10ECh. 6 - Prob. 11ECh. 6 - Prob. 12ECh. 6 - Prob. 13ECh. 6 - Prob. 14ECh. 6 - Prob. 15ECh. 6 - Prob. 16ECh. 6 - Prob. 17ECh. 6 - Prob. 18ECh. 6 - Prob. 19ECh. 6 - Prob. 20ECh. 6 - Prob. 21ECh. 6 - Prob. 22ECh. 6 - Prob. 23ECh. 6 - Prob. 24ECh. 6 - Prob. 25ECh. 6 - Prob. 26ECh. 6 - Prob. 27ECh. 6 - Prob. 28ECh. 6 - Prob. 29ECh. 6 - Prob. 30ECh. 6 - Prob. 31ECh. 6 - Prob. 32ECh. 6 - Prob. 33ECh. 6 - Prob. 34ECh. 6 - Prob. 35ECh. 6 - Prob. 36ECh. 6 - Prob. 37ECh. 6 - Prob. 38ECh. 6 - Prob. 39ECh. 6 - Prob. 40ECh. 6 - Prob. 41ECh. 6 - Prob. 42ECh. 6 - Prob. 43ECh. 6 - Prob. 44ECh. 6 - Prob. 45ECh. 6 - Prob. 46ECh. 6 - Prob. 47ECh. 6 - Prob. 48ECh. 6 - Prob. 49ECh. 6 - Prob. 50ECh. 6 - Prob. 51ECh. 6 - Prob. 52ECh. 6 - Prob. 53ECh. 6 - Prob. 54ECh. 6 - Prob. 55ECh. 6 - Prob. 56ECh. 6 - Prob. 57ECh. 6 - Prob. 58ECh. 6 - Prob. 59ECh. 6 - Prob. 60ECh. 6 - Prob. 61ECh. 6 - Prob. 62ECh. 6 - Prob. 63ECh. 6 - Prob. 64ECh. 6 - Prob. 65ECh. 6 - Prob. 66ECh. 6 - Prob. 67ECh. 6 - Prob. 68ECh. 6 - Prob. 69ECh. 6 - Prob. 70ECh. 6 - Prob. 71ECh. 6 - Prob. 72ECh. 6 - Prob. 73ECh. 6 - Prob. 74ECh. 6 - Prob. 75ECh. 6 - Prob. 76ECh. 6 - Prob. 77ECh. 6 - Prob. 78ECh. 6 - Prob. 79ECh. 6 - Prob. 80ECh. 6 - Prob. 1STCh. 6 - Prob. 2STCh. 6 - Prob. 3STCh. 6 - Prob. 4STCh. 6 - Prob. 5STCh. 6 - Prob. 6STCh. 6 - Prob. 7STCh. 6 - Prob. 8STCh. 6 - Prob. 9STCh. 6 - Prob. 10STCh. 6 - Prob. 11STCh. 6 - Prob. 12STCh. 6 - Prob. 13STCh. 6 - Prob. 14STCh. 6 - Prob. 15STCh. 6 - Prob. 16STCh. 6 - Prob. 17STCh. 6 - Prob. 18STCh. 6 - Prob. 19STCh. 6 - Prob. 20ST
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