Chapter 6, Problem 18E

Interpretation Introduction

(a)

Interpretation:

The chemical formula for the ternary compound, sodium acetate, given its constituent atoms, ${\text{Na}}^{\text{+}}$ and ${\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}{}^{-}$, is to be stated.

Concept introduction:

Compounds containing a metal and more than one other element are termed as ternary ionic compounds. The charge on the ternary ionic compounds must always be neutral.

Answer to Problem 18E

The chemical formula for the ternary compound, sodium acetate is $\text{Na}\left({\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\right)$.

Explanation of Solution

The ternary compound sodium acetate contains ${\text{Na}}^{\text{+}}$ and ${\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}{}^{-}$ as constituent ions. The sodium ion has a charge of $+1$ and the acetate ion has a charge of $-1$. One positive ion is required for each negative ion in the formula unit. Therefore, the chemical formula of sodium acetate is $\text{Na}\left({\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\right)$.

Conclusion

The chemical formula for the ternary compound, sodium acetate is $\text{Na}\left({\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\right)$.

Interpretation Introduction

(b)

Interpretation:

The chemical formula for the ternary compound, aluminum sulfite, given its constituent atoms, ${\text{Al}}^{3+}$ and ${\text{SO}}_3^{2-}$, is to be stated.

Concept introduction:

Compounds containing a metal and more than one other element are termed as ternary ionic compounds. The charge on the ternary ionic compounds must always be neutral

Answer to Problem 18E

The chemical formula for the ternary compound, aluminum sulfite is ${\text{Al}}_{\text{2}}{\left({\text{SO}}_3\right)}_3$.

Explanation of Solution

The ternary compound, aluminum sulfite contains ${\text{Al}}^{3+}$ and ${\text{SO}}_3^{2-}$ as constituent ions. The ${\text{Al}}^{3+}$ ion has a charge of $+3$ and the ${\text{SO}}_3^{2-}$ ion has a charge of $-2$. Therefore, two positive ions are required to cancel the charge of three negative ions in the formula unit. Therefore, the chemical formula of aluminum sulfite is ${\text{Al}}_{\text{2}}{\left({\text{SO}}_3\right)}_3$.

Conclusion

The chemical formula for the ternary compound, aluminum sulfite is ${\text{Al}}_{\text{2}}{\left({\text{SO}}_3\right)}_3$.

Interpretation Introduction

(c)

Interpretation:

The chemical formula for the ternary compound, mercury $\left(\text{II}\right)$ cyanide, given its constituent atoms, ${\text{Hg}}^{2+}$ and ${\text{CN}}^{-}$, is to be stated.

Concept introduction:

Compounds containing a metal and more than one other element are termed as ternary ionic compounds. The charge on the ternary ionic compounds must always be neutral

Answer to Problem 18E

The chemical formula for the ternary compound, mercury $\left(\text{II}\right)$ cyanide is $\text{Hg}{\left(\text{CN}\right)}_2$.

Explanation of Solution

The ternary compound, mercury $\left(\text{II}\right)$ cyanide contains ${\text{Hg}}^{2+}$ and ${\text{CN}}^{-}$ as constituent ions. The ${\text{Hg}}^{2+}$ ion has a charge of $+2$ and the ${\text{CN}}^{-}$ ion has a charge of $-1$. Therefore, two negative ions are required for each positive ion in the formula unit. Therefore, the chemical formula of mercury $\left(\text{II}\right)$ cyanide is $\text{Hg}{\left(\text{CN}\right)}_2$.

Conclusion

The chemical formula for the ternary compound, mercury $\left(\text{II}\right)$ cyanide is $\text{Hg}{\left(\text{CN}\right)}_2$.

Interpretation Introduction

(d)

Interpretation:

The chemical formula for the ternary compound, chromium $\left(\text{III}\right)$ hypochlorite, given its constituent atoms, ${\text{Cr}}^{\text{3+}}$ and ${\text{ClO}}^{-}$, is to be stated.

Concept introduction:

Compounds containing a metal and more than one other element are termed as ternary ionic compounds. The charge on the ternary ionic compounds must always be neutral

Answer to Problem 18E

The chemical formula for the ternary compound, chromium $\left(\text{III}\right)$ hypochlorite, is $\text{Cr}{\left(\text{ClO}\right)}_{\text{3}}$.

Explanation of Solution

The ternary compound, chromium $\left(\text{III}\right)$ hypochlorite contains ${\text{Cr}}^{\text{3+}}$ and ${\text{ClO}}^{-}$ as constituent ions. The ${\text{Cr}}^{\text{3+}}$ ion has a charge of $+3$ and the ${\text{ClO}}^{-}$ ion has a charge of $-1$. Therefore, one positive ions is required to cancel the charge of three negative ions in the formula unit. Therefore, the chemical formula of chromium $\left(\text{III}\right)$ hypochlorite, is $\text{Cr}{\left(\text{ClO}\right)}_{\text{3}}$.

Conclusion

The chemical formula for the ternary compound, chromium $\left(\text{III}\right)$ hypochlorite, is $\text{Cr}{\left(\text{ClO}\right)}_{\text{3}}$.