Chapter 6, Problem 20E

Interpretation Introduction

(a)

Interpretation:

The chemical formula for the ternary compound, lead $\left(\text{IV}\right)$ sulfate, given its constituent atoms, ${\text{Pb}}^{\text{4+}}$ and ${\text{SO}}_{\text{4}}{}^{2-}$, is to be stated.

Concept introduction:

Compounds containing a metal and more than one other element are termed as ternary ionic compounds. The charge on the ternary ionic compounds must always be neutral, no matter what the charges on the individual ions are.

Answer to Problem 20E

The chemical formula for the ternary compound, lead $\left(\text{IV}\right)$ sulfate is $\text{Pb}{\left({\text{SO}}_{\text{4}}\right)}_2$.

Explanation of Solution

The ternary compound, lead $\left(\text{IV}\right)$ sulfate contains ${\text{Pb}}^{\text{4+}}$ and ${\text{SO}}_{\text{4}}{}^{2-}$ as constituent ions. The ${\text{Pb}}^{\text{4+}}$ ion has a charge of $+4$ and the ${\text{SO}}_{\text{4}}{}^{2-}$ ion has a charge of $-2$. Two negative ions are required to cancel the charge of one positive ion in the formula unit. Therefore, the chemical formula of lead $\left(\text{IV}\right)$ sulfate is $\text{Pb}{\left({\text{SO}}_{\text{4}}\right)}_2$.

Conclusion

The chemical formula for the ternary compound, lead $\left(\text{IV}\right)$ sulfate is $\text{Pb}{\left({\text{SO}}_{\text{4}}\right)}_2$.

Interpretation Introduction

(b)

Interpretation:

The chemical formula for the ternary compound, tin $\left(\text{II}\right)$ chlorite, given its constituent atoms, ${\text{Sn}}^{2+}$ and ${\text{ClO}}_2{}^{-}$, is to be stated.

Concept introduction:

Compounds containing a metal and more than one other element are termed as ternary ionic compounds. The charge on the ternary ionic compounds must always be neutral, no matter what the charges on the individual ions are.

Answer to Problem 20E

The chemical formula for the ternary compound, tin $\left(\text{II}\right)$ chlorite is $\text{Sn}{\left({\text{ClO}}_2\right)}_2$.

Explanation of Solution

The ternary compound, tin $\left(\text{II}\right)$ chlorite contains ${\text{Sn}}^{2+}$ and ${\text{ClO}}_2{}^{-}$ as constituent ions. The ${\text{Sn}}^{2+}$ ion has a charge of $+2$ and the ${\text{ClO}}_2{}^{-}$ ion has a charge of $-1$. Therefore, two negative ions are required to cancel the charge of one positive ion in the formula unit. Therefore, the chemical formula of tin $\left(\text{II}\right)$ chlorite is $\text{Sn}{\left({\text{ClO}}_2\right)}_2$.

Conclusion

The chemical formula for the ternary compound, tin $\left(\text{II}\right)$ chlorite is $\text{Sn}{\left({\text{ClO}}_2\right)}_2$.

Interpretation Introduction

(c)

Interpretation:

The chemical formula for the ternary compound, cobalt $\left(\text{II}\right)$ hydroxide, given its constituent atoms, ${\text{Co}}^{2+}$ and ${\text{OH}}^{-}$, is to be stated.

Concept introduction:

Compounds containing a metal and more than one other element are termed as ternary ionic compounds. The charge on the ternary ionic compounds must always be neutral, no matter what the charges on the individual ions are.

Answer to Problem 20E

The chemical formula for the ternary compound, cobalt $\left(\text{II}\right)$ hydroxide is $\text{Co}{\left(\text{OH}\right)}_2$.

Explanation of Solution

The ternary compound, cobalt $\left(\text{II}\right)$ hydroxide contains ${\text{Co}}^{2+}$ and ${\text{OH}}^{-}$ as constituent ions. The ${\text{Co}}^{2+}$ ion has a charge of $+2$ and the ${\text{OH}}^{-}$ ion has a charge of $-1$. Therefore, two negative ions are required for each positive ion in the formula unit. Therefore, the chemical formula of cobalt $\left(\text{II}\right)$ hydroxide is $\text{Co}{\left(\text{OH}\right)}_2$.

Conclusion

The chemical formula for the ternary compound, cobalt $\left(\text{II}\right)$ hydroxide is $\text{Co}{\left(\text{OH}\right)}_2$.

Interpretation Introduction

(d)

Interpretation:

The chemical formula for the ternary compound, mercury $\left(\text{I}\right)$ phosphate, given its constituent atoms, ${\text{Hg}}_2{}^{\text{2+}}$ and ${\text{PO}}_4{}^{3-}$, is to be stated.

Concept introduction:

Compounds containing a metal and more than one other element are termed as ternary ionic compounds. The charge on the ternary ionic compounds must always be neutral, no matter what the charges on the individual ions are.

Answer to Problem 20E

The chemical formula for the ternary compound, mercury $\left(\text{I}\right)$ phosphate is ${\text{Hg}}_3{\left({\text{PO}}_4\right)}_{\text{2}}$.

Explanation of Solution

The ternary compound, mercury $\left(\text{I}\right)$ phosphate contains ${\text{Hg}}_2{}^{\text{2+}}$ and ${\text{PO}}_4{}^{3-}$ as constituent ions. The ${\text{Hg}}_2{}^{\text{2+}}$ ion has a charge of $+2$ and the ${\text{PO}}_4{}^{3-}$ ion has a charge of $-3$. Therefore, three positive ions are required to cancel the charge of two negative ions in the formula unit. Therefore, the chemical formula of mercury $\left(\text{I}\right)$ phosphate is ${\text{Hg}}_3{\left({\text{PO}}_4\right)}_{\text{2}}$.

Conclusion

The chemical formula for the ternary compound, mercury $\left(\text{I}\right)$ phosphate is ${\text{Hg}}_3{\left({\text{PO}}_4\right)}_{\text{2}}$.