Concept explainers
For t < 0, an object of mass m experiences no force and moves in the positive x direction with a constant speed vi. Beginning at t = 0, when the object passes position x = 0, it experiences a net resistive force proportional to the square of its speed:
Want to see the full answer?
Check out a sample textbook solutionChapter 6 Solutions
Physics for Scientists and Engineers with Modern Physics
Additional Science Textbook Solutions
College Physics: A Strategic Approach (3rd Edition)
Brock Biology of Microorganisms (15th Edition)
Fundamentals Of Thermodynamics
Applications and Investigations in Earth Science (9th Edition)
Laboratory Experiments in Microbiology (12th Edition) (What's New in Microbiology)
- A 20-kg particle moves with this trajectory: r ( t ) = − 40 t ȷ ^ + 25 t ı ^ + ( 5 ı ^ − 8 ȷ ^ ) e − 5 t Calculate the force on the particle. (Units are meters, seconds, and Newtons.)arrow_forwardO 0.2 MPa A 3500 Ib. car moving at 25 mi/h is accelerated at a constant rate of 15 ft/s^2^ up to a speed of 50 mi/h. What are the force and total time required? * O 1632 Ibf, 183 s O 7523 Ibf, 175 s O 52500 Ibf, 183 s O 7523 Ibf, 183 s O 1832 Ibf, 175 s O 2083 Ibf, 175 s • Document 14 5jpg O O O OO 0arrow_forward77 X 7. A roller coaster reaches the top of the steepest hill with a speed of 6.80 km/h. It then descends the hill, which is at an average angle of 40° and is 59.0 m long. What will its speed be when it reaches the bottom? Assume Hk = 0.16. m/s E C 4 F T G B MacBook Air H U N J WA M K MOSISO भ command optionarrow_forward
- A theme park is planning out a new free-fall ride. The drop is almost perfectly frictionless, with a distance of 190 meters. Assuming that the initial velocity was zero, what would be the speed at the bottom of the drop? 1 53 m/s 2 61 m/s 3 67 m/s 4 72 m/sarrow_forwardA wagon with its passenger sits at the top of a hill. A strong wind suddenly rolls the wagon 188m down a 28 degree incline to the bottom of the hill. What is the wagons speed in m/s? Assume friction is negligible.arrow_forwardA small boat is crossing a lake on a windy day. During some interval of time, the boat undergoes the given displacement Δ?⃗ .Δr→. Δ?⃗ =(3.19 m)ı̂ +(2.89 m)ȷ̂ Δr→=(3.19 m)ı^+(2.89 m)ȷ^ During the same interval of time, the wind exerts the given constant force ?⃗ F→ on the boat. ?⃗ =(261 N)ı̂ −(125 N)ȷ̂arrow_forward
- An object with a mass of 1.76 kg is initially at rest upon a horizontal, frictionless surface. An applied force of 3.04 N i acts on the object for 2.08 s. What is the object's final speed? Enter a number rounded to 2 decimal places and assume the answer has proper SI Units.arrow_forwardA parachutist whose mass is 85 kg drops from a helicopter hovering 2000 m above the ground and falls toward the ground under the influence of gravity. Assume that the force due to air resistance is proportional to the velocity of the parachutist, with the proportionality constant b 1 = 20 N - sec/m when the chute is closed and b 2 = 90 N - sec/m when the chute is open. If the chute does not open until the velocity of the parachutist reaches 35 m/sec, after how many seconds will the parachutist reach the ground? Assume that the acceleration due to gravity is 9.81 m/ sec ^2arrow_forwardThree youths push a 40.0-kg block of ice so that it begins to coast on a frozen lake. With an initial speed Vi of 3.00 m/s, the block of ice now moves up an icy ramp at the edge of the lake. Neglecting air resistance and in the absence of any friction between the ice block and the frozen lake and ramp, use the CMEP to calculate how high up the ramp (h in the figure) the block of ice moves before stopping. As a suggestion, use the base of the ramp as GZ. 0.204 m 0.625 m 0.459 m 0.511 m 0.165 m 0.270 m O O Oarrow_forward
- A parachutist whose mass is 65 kg drops from a helicopter hovering 2500 m above the ground and falls toward the ground under the influence of gravity. Assume that the force due to air resistance is proportional to the velocity of the parachutist, with the proportionality constant b_1 = 20 N*sec/m when the chute is closed and b_2 = 90 N*sec/m when the chute is open. If the chute does not open until the velocity of the parachutist reaches 25 m/sec, after how many seconds will the parachutist reach the ground? Assume that the acceleration due to gravity is 9.81 m/sec^2. How much time will the parachutist reach the ground after? (Round up your answer to two decimal places as needed.)arrow_forwarda 2 kg golf ball moves along an x axis according to x(t) = 10t^3 - 2.80t^2 + 7.4t +15 , with x in meters and t in seconds . in unit-vector notation , what is the net force acting on the particle at t= 5.20 s?arrow_forwardA particle of mass 1 g is moving along the positive x-axis under the influence of a force. k F = - x2 where k= 10-3 Nm?. When the particle is at x = 1.0 m, its velocity v = 0. Find (a) the magnitude of its velocity when, it reaches x=0.5 m and (b) its position when its speed is 1 ms'.arrow_forward
- Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning