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(a)
Interpretation:
The preparation of 1.00L 0.5 M of each given solutions using volumetric principles are should be explained.
Concept Introduction:
Dilution is to save time and space in the laboratory, routinely used solutions are often purchased or prepared in concentrated form (called stock solution).
Water is then added to achieve the molarity desired for a particular solution. This process is
Called Dilution
Molarity is the number of moles of solute per liter of solution.
To dilute a stock solution, the following dilution equation is used:
Formula,
M1 V1 = M2 V2. (1)
M1 and V1 are the molarity and volume of the concentrated stock solution,
M2 and V2 are the molarity and volume of the diluted solution you want to make.
(b)
Interpretation:
The preparation of 1.00L 0.5 M of each given solutions using volumetric principles are should be explained.
Concept Introduction:
Dilution is to save time and space in the laboratory, routinely used solutions are often purchased or prepared in concentrated form (called stock solution).
Water is then added to achieve the molarity desired for a particular solution. This process is
Called Dilution
Molarity is the number of moles of solute per liter of solution.
To dilute a stock solution, the following dilution equation is used:
Formula,
M1 V1 = M2 V2. (1)
M1 and V1 are the molarity and volume of the concentrated stock solution,
M2 and V2 are the molarity and volume of the diluted solution you want to make.
(c)
Interpretation:
The preparation of 1.00L 0.5 M of each given solutions using volumetric principles are should be explained.
Concept Introduction:
Dilution is to save time and space in the laboratory, routinely used solutions are often purchased or prepared in concentrated form (called stock solution).
Water is then added to achieve the molarity desired for a particular solution. This process is
Called Dilution
Molarity is the number of moles of solute per liter of solution.
To dilute a stock solution, the following dilution equation is used:
Formula,
M1 V1 = M2 V2. (1)
M1 and V1 are the molarity and volume of the concentrated stock solution,
M2 and V2 are the molarity and volume of the diluted solution you want to make.
(d)
Interpretation:
The preparation of 1.00L 0.5 M of each given solutions using volumetric principles are should be explained.
Concept Introduction:
Dilution is to save time and space in the laboratory, routinely used solutions are often purchased or prepared in concentrated form (called stock solution).
Water is then added to achieve the molarity desired for a particular solution. This process is
Called Dilution
Molarity is the number of moles of solute per liter of solution.
To dilute a stock solution, the following dilution equation is used:
Formula,
M1 V1 = M2 V2. (1)
M1 and V1 are the molarity and volume of the concentrated stock solution,
M2 and V2 are the molarity and volume of the diluted solution you want to make.
(e)
Interpretation:
The preparation of 1.00L 0.5 M of each given solutions using volumetric principles are should be explained.
Concept Introduction:
Dilution is to save time and space in the laboratory, routinely used solutions are often purchased or prepared in concentrated form (called stock solution).
Water is then added to achieve the molarity desired for a particular solution. This process is
Called Dilution
Molarity is the number of moles of solute per liter of solution.
To dilute a stock solution, the following dilution equation is used:
Formula,
M1 V1 = M2 V2. (1)
M1 and V1 are the molarity and volume of the concentrated stock solution,
M2 and V2 are the molarity and volume of the diluted solution you want to make.
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Chapter 6 Solutions
Bundle: Chemistry: An Atoms First Approach, 2nd, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card
- Nonearrow_forwardIn the phase diagram of steel (two components Fe and C), region A is the gamma austenite solid and region B contains the gamma solid and liquid. Indicate the degrees of freedom that the fields A and B have,arrow_forwardFor a condensed binary system in equilibrium at constant pressure, indicate the maximum number of phases that can exist.arrow_forward
- Part V. Label ad match the carbons in compounds Jane and Diane w/ the corresponding peak no. in the Spectra (Note: use the given peak no. To label the carbons, other peak no are intentionally omitted) 7 4 2 -0.13 -0.12 -0.11 -0.10 -0.08 8 CI Jane 1 -0.09 5 210 200 190 180 170 160 150 140 130 120 110 100 -8 90 f1 (ppm) 11 8 172.4 172.0 f1 (ppr HO CI NH Diane 7 3 11 80 80 -80 -R 70 60 60 2 5 -8 50 40 8. 170 160 150 140 130 120 110 100 90 -0 80 70 20 f1 (ppm) 15 30 -20 20 -60 60 -0.07 -0.06 -0.05 -0.04 -0.03 -0.02 -0.01 -0.00 -0.01 10 -0.17 16 15 56 16 -0.16 -0.15 -0.14 -0.13 -0.12 -0.11 -0.10 -0.09 -0.08 -0.07 -0.06 -0.05 -0.04 17.8 17.6 17.4 17.2 17.0 f1 (ppm) -0.03 -0.02 550 106 40 30 20 20 -0.01 -0.00 F-0.01 10 0arrow_forwardConsider the reaction of 2-methylpropane with a halogen. With which halogen will the product be almost exclusively 2-halo-2-methylpropane? 1. F2 2. Cl2 3. Br2 4. I2arrow_forwardNonearrow_forward
- Nonearrow_forwardn Feb 3 A T + 4. (2 pts) Draw the structure of the major component of the Limonene isolated. Explain how you confirmed the structure. 5. (2 pts) Draw the fragment corresponding to the base peak in the Mass spectrum of Limonene. 6. (1 pts) Predict the 1H NMR spectral data of R-Limonene. Proton NMR: 5.3 pon multiplet (H Ringarrow_forwardPart VI. Ca H 10 O is the molecular formula of compound Tom and gives the in the table below. Give a possible structure for compound Tom. 13C Signals summarized C1 C2 C3 C4 C5 C6 C7 13C shift (ppm) 23.5 27.0 33.0 35.8 127 162 205 DEPT-90 + DEPT-135 + +arrow_forward
- 2. Using the following data to calculate the value of AvapH o of water at 298K. AvapH o of water at 373K is 40.7 kJ/mol; molar heat capacity of liquid water at constant pressure is 75.2J mol-1 K-1 and molar heat capacity of water vapor at constant pressure is 33.6 J mol-1 K-1.arrow_forwardPart VII. Below are the 'HNMR 13 3 C-NMR, COSY 2D- NMR, and HSQC 20-NMR (Similar with HETCOR but axes are reversed) spectra of an organic compound with molecular formula C6H13 O. Assign chemical shift values to the H and c atoms of the compound. Find the structure. Show complete solutions. Predicted 1H NMR Spectrum ли 4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1.0 0.9 0.8 f1 (ppm)arrow_forward3. Draw the expanded structural formula, the condensed structural formula, and the skeletal structural formula for 2-pentene. expanded structure: Condensed structure: Skeletal formula: 4. Draw the expanded structural formula, the condensed structural formula, and the skeletal structural formula for 2-methyl-3-heptene. expanded structure: Condensed structure: Skeletal formula: following structurearrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStax
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