Chapter 6, Problem 26E

(a)

Interpretation Introduction

Interpretation: The value of $K_{\text{P}}$ for indicated reaction is to be calculated.

  $\text{HBr}\left(g\right)\rightleftharpoons \frac{1}{2}{\text{H}}_{\text{2}}\left(g\right)+\frac{1}{2}{\text{Br}}_2\left(g\right)$

Concept introduction:Characteristics of $K$ or $K_{\text{P}}$ is that for a reverse reaction magnitude of $K$ for new reaction is reciprocal of original $K$ .

For a reaction multiplied by $n$ factor then magnitude of $K$ for new reaction is given as follows:

  $K_{\text{new}}={\left(K_{\text{original}}\right)}^n$

(b)

Interpretation Introduction

Interpretation: The value of $K_{\text{P}}$ for indicated reaction is to be calculated.

  $2\text{HBr}\left(g\right)\rightleftharpoons {\text{H}}_{\text{2}}\left(g\right)+{\text{Br}}_2\left(g\right)$

Concept introduction: Characteristics of $K$ or $K_{\text{P}}$ is that for a reverse reaction magnitude of $K$ for new reaction is reciprocal of original $K$ .

For a reaction multiplied by $n$ factor then magnitude of $K$ for new reaction is given as follows:

  $K_{\text{new}}={\left(K_{\text{original}}\right)}^n$

(c)

Interpretation Introduction

Interpretation: The value of $K_{\text{P}}$ for indicated reaction is to be calculated.

  $\frac{1}{2}{\text{H}}_{\text{2}}\left(g\right)+\frac{1}{2}{\text{Br}}_2\left(g\right)\rightleftharpoons \text{HBr}\left(g\right)$

Concept introduction: Characteristics of $K$ or $K_{\text{P}}$ is that for a reverse reaction magnitude of $K$ for new reaction is reciprocal of original $K$ .

For a reaction multiplied by $n$ factor then magnitude of $K$ for new reaction is given as follows:

  $K_{\text{new}}={\left(K_{\text{original}}\right)}^n$