(a)
Interpretation:
Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.
Concept Introduction:
Strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.
(a)
Answer to Problem 25E
The dissociation of the given strong electrolyte is,
Explanation of Solution
Figure 1
Let us consider the above molecular-level pictures of
number of
(b)
Interpretation:
Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.
Concept Introduction:
Strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.
(b)
Answer to Problem 25E
The dissociation of the given strong electrolyte is,.
Explanation of Solution
To draw the molecular-level pictures of
Figure 2
Let us consider the above molecular-level pictures of
number of
(c)
Interpretation:
Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.
Concept Introduction:
Strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.
(c)
Answer to Problem 25E
The dissociation of the given strong electrolyte is,
Explanation of Solution
To draw the molecular-level pictures of
Figure 3
Let us consider the above molecular-level pictures of
number of
should show equal
number of
(d)
Interpretation:
Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.
Concept Introduction:
Strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.
(d)
Answer to Problem 25E
The dissociation of the given strong electrolyte is,
Explanation of Solution
To draw the molecular-level pictures of
Figure 4
Let us consider the above molecular-level pictures of
number of
(e)
Interpretation:
Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.
Concept Introduction:
Strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.
(e)
Answer to Problem 25E
The dissociation of the given strong electrolyte is,
Explanation of Solution
To draw the molecular-level pictures of
Figure 5
Let us consider the above molecular-level pictures of
Number of
(f)
Interpretation:
Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.
Concept Introduction:
Strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.
(f)
Answer to Problem 25E
The dissociation of the given strong electrolyte is,
Explanation of Solution
To draw the molecular-level pictures of
Figure 6
Let us consider the above molecular-level pictures of
number of
(g)
Interpretation:
Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.
Concept Introduction:
Strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.
(g)
Answer to Problem 25E
The dissociation of the given strong electrolyte is,
Explanation of Solution
To draw the molecular-level pictures of
Figure 7
Let us consider the above molecular-level pictures of
number of
(h)
Interpretation:
Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.
Concept Introduction:
Strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.
(h)
Answer to Problem 25E
The dissociation of the given strong electrolyte is,
Explanation of Solution
To draw the molecular-level pictures of
Figure 8
Let us consider the above molecular-level pictures of
number of
(i)
Interpretation:
Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.
Concept Introduction:
Strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.
(i)
Answer to Problem 25E
The dissociation of the given strong electrolyte is,
Explanation of Solution
To draw the molecular-level pictures of
Figure 9
Let us consider the above molecular-level pictures of
Number of
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Chapter 6 Solutions
EBK CHEMISTRY: AN ATOMS FIRST APPROACH
- What volume of 0.250 M HCI is required to neutralize each of the following solutions? a. 25.0 mL of 0.103 M sodium hydroxide, NaOH b. 50.0 mL of 0.00501 M calcium hydroxide, Ca(OH)2 c. 20.0 mL of 0.226 M ammonia, NH3 d. 15.0 mL of 0.0991 M potassium hydroxide, KOHarrow_forwardThe (aq) designation listed after a solute indicates the process of hydration. Using KBr(aq) and C2H5OH(aq) as your examples, explain the process of hydration for soluble ionic compounds and for soluble covalent compounds.arrow_forwardssume a highly magnified view of a solution of HCI that allows you to “see” the HCl. Draw this magnified view. If you dropped in a piece of magnesium, the magnesium would disappear, and hydrogen gas would he released. Represent this change using symbols for the elements, and write the balanced equation.arrow_forward
- efine the term strong electrolyte. What types of substances tend to be strong electrolytes? What does a solution of a strong electrolyte contain? Give a way to determine if a substance is a strong electrolyte.arrow_forwardA 10.00-mL sample of a 24.00% solution of ammonium bromide (NH4Br) requires 23.41 mL of 1.200 molar silver nitrate (AgNO3) to react with all of the bromide ion present. (a) Calculate the molarity of the ammonium bromide solution. (b) Use the molarity of the solution to find the mass of ammonium bromide in 1.000 L of this solution. (c) From the percentage concentration and the answer to part b, find the mass of 1.000 L ammonium bromide solution. (d) Combine the answer to part c with the volume of 1.000 L to express the density of the ammonium bromide solution (in g/mL).arrow_forwardDescribe some physical and chemical properties of acids and bases. What is meant by a strong acid or base? Are strong acids and bases also strong electrolytes? Give several examples of strong acids and strong bases.arrow_forward
- Lead poisoning has been a hazard for centuries. Some scholars believe that the decline of the Roman Empire can be traced, in part, to high levels of lead in water from containers and pipes, and from wine that was stored in leadglazed containers. If we presume that the typical Roman water supply was saturated with lead carbonate, PbCO3 (Ksp = 7.4 1014), how much lead will a Roman ingest in a year if he or she drinks 1 L/day from the container?arrow_forwardA mountain lake that is 4.0 km × 6.0 km with an average depth of 75 m has an H+(aq) concentration of 1.3 × 10−6 M. Calculate the mass of calcium carbonate that would have to be added to the lake to change the H+(aq) concentration to 6.3 × 10−8 M. Assume that all the carbonate is converted to carbon dioxide, which bubbles out of the solution.arrow_forwardWorking with Concentration (Molarity Concepts) Note: You should be able to answer all of the following questions without using a calculator. Part 1: a Both NaCl and MgCl2 are soluble ionic compounds. Write the balanced chemical equations for these two substances dissolving in water. b Consider the pictures below. These pictures represent 1.0-L solutions of 1.0 M NaCl(aq) and 1.0 M MgCl2(aq). The representations of the ions in solution are the correct relative amounts. Water molecules have been omitted for clarity. Correctly label each of the beakers, provide a key to help identify the ions, and give a brief explanation of how you made your assignments. Keeping in mind that the pictures represent the relative amounts of ions in the solution and that the numerical information about these solutions is presented above, answer the following questions c through f. c How many moles of NaCl and MgCl2 are in each beaker? d How many moles of chloride ions are in each beaker? How did you arrive at this answer? e What is the concentration of chloride ions in each beaker? Without using mathematical equations, briefly explain how you obtained your answer. f Explain how it is that the concentrations of chloride ions in these beakers are different even though the concentrations of each substance (compound) are the same. Part 2: Say you were to dump out half of the MgCl2 solution from the beaker above. a What would be the concentration of the MgCl2(aq) and of the chloride ions in the remaining solution? b How many moles of the MgCl2 and of the chloride ions would remain in the beaker? c Explain why the concentration of MgCl2(aq) would not change, whereas the number of moles of MgCl2 would change when solution was removed from the beaker. As part of your answer, you are encouraged to use pictures. Part 3: Consider the beaker containing 1.0 L of the 1.0 M NaCl(aq) solution. You now add 1.0 L of water to this beaker. a What is the concentration of this NaCl(aq) solution? b How many moles of NaCl are present in the 2.0 L of NaCl(aq) solution? c Explain why the concentration of NaCl(aq) does change with the addition of water, whereas the number of moles does not change. Here again, you are encouraged to use pictures to help answer the question.arrow_forward
- 3.64 How many grams of solute are present in each of these solutions? (a) 37.2 mL ofO.471 M HBr (b) 113.0 L of 1.43 M Na2CO3 (c) 212 mL of 6.8 M CH3COOH (d) 1.3 × 10-4 L of 1.03 M H2S03arrow_forwardEqual quantities of the hypothetical strong acid HX, weak acid HA, and weak base BZ are added to separate beakers of water, producing the solutions depicted in the drawings. In the drawings, the relative amounts of each substance present in the solution (neglecting the water) are shown. Identify the acid or base that was used to produce each of the solutions (HX, HA, or BZ).arrow_forwardTwo liters of a 1.5 M solution of sodium hydroxide are needed for a laboratory experiment. A stock solution of 5.0 M NaOH is available. How is the desired solution prepared?arrow_forward
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