The given following terms has to be differentiated. Concept introduction: Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction . Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction. Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors. Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors. 2CuCl (aq) +Mg (s) → 2Cu (s) +MgCl 2(aq) In your equation, Mg went from 0 oxidation number to +2 , loss electrons got oxidized is the reducing agent Cu went from +1 to 0 gained an electron, got reduced is the oxidizing agent

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Answer 1

Question

Chapter 6, Problem 23Q

(a)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

(b)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

(c)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

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Answer 2

Question

Chapter 6, Problem 23Q

(a)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

(b)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

(c)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

Expert Solution & Answer

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Answer 3

Question

Chapter 6, Problem 23Q

(a)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

(b)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

(c)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 6, Problem 23Q

(a)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

(b)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

(c)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 6, Problem 23Q

(a)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

(b)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

(c)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

Answer 6

Chapter 6, Problem 23Q

(a)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

Answer 7

Chapter 6, Problem 23Q

(a)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

Answer 8

(b)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

Answer 9

(b)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

Answer 10

(c)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

Answer 11

(c)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

$2CuCl(aq)+Mg(s)→2Cu(s)+MgCl2(aq)$

In your equation, $Mg$ went from 0 oxidation number to $+2$ , loss electrons got oxidized is the reducing agent

$Cu$ went from $+1 to 0$ gained an electron, got reduced is the oxidizing agent

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

Ch. 6 - The (aq) designation listed after a solute...Ch. 6 - Characterize strong electrolytes versus weak...Ch. 6 - Distinguish between the terms slightly soluble and...Ch. 6 - Prob. 4RQ Ch. 6 - Prob. 5RQ Ch. 6 - When the following beakers are mixed, draw a...Ch. 6 - Prob. 7RQ Ch. 6 - What is an acid-base reaction? Strong bases are...Ch. 6 - Prob. 9RQ Ch. 6 - Assume you have a highly magnified view of a...

Solution Summary: The author explains that oxidation is the process by which a molecule, atom or ion loses its electron in chemical reaction. Reducing agents are chemical substances that generally lose electrons.

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