A reducing elbow in a horizontal pipe is used to deflect water flow by an angle θ = 450 from the flow direction while accelerating it. The elbow discharges water into the atmosphere. The cross-sectional area of the elbow is 150 cm2 at the inlet and 25 cm 2 at the exit. The elevation difference betwecn the centers of the exit and the inlet is 40 cm. The mass of the elbow and the water in it is 50 kg. Determine the anchoring force needed to hold the elbow in place. Take the momentum-flux correction factor to be 1.03 at both the inlet and outlet.
A reducing elbow in a horizontal pipe is used to deflect water flow by an angle θ = 450 from the flow direction while accelerating it. The elbow discharges water into the atmosphere. The cross-sectional area of the elbow is 150 cm2 at the inlet and 25 cm 2 at the exit. The elevation difference betwecn the centers of the exit and the inlet is 40 cm. The mass of the elbow and the water in it is 50 kg. Determine the anchoring force needed to hold the elbow in place. Take the momentum-flux correction factor to be 1.03 at both the inlet and outlet.
A reducing elbow in a horizontal pipe is used to deflect water flow by an angle
θ
=
450
from the flow direction while accelerating it. The elbow discharges water into the atmosphere. The cross-sectional area of the elbow is 150 cm2 at the inlet and 25 cm2 at the exit. The elevation difference betwecn the centers of the exit and the inlet is 40 cm. The mass of the elbow and the water in it is 50 kg. Determine the anchoring force needed to hold the elbow in place. Take the momentum-flux correction factor to be 1.03 at both the inlet and outlet.
A bent pipe is attached to a wall with brackets as shown. A
force of F = 180 lb is applied to the end of the tube with
direction indicated by the dimensions in the figure.
Determine the support reactions at the brackets B, C, and
D. Model these brackets as journal bearings (only force
reactions perpendicular to the axis of the tube) and neglect
couple moment reactions. Assume the distance between the
supports at B and C and the tube bends nearby are
negligible such that the support at C is directly above the
support at D and the dimension g gives the distance between
supports B and C. Enter your answers in Cartesian
components.
2013 Michael Swanbom
cc 10
BY NC SA
g
h
א
B
8°
У
A
C
x
каж
Values for dimensions on the figure are given in the table
below. Note the figure may not be to scale.
Variable Value
a
6.72 in
b
11.8 in
с
14.8 in
d
42.0 in
h
26.6 in
g
28.0 in
→
The reaction at B is B =
lb.
The reaction at C is C =
lb.
The reaction at D is D =
lb.
+
<<
+
+
2.
+
+
557
〈ん
The force F1 = 10 kN, F2 = 10 kN, F3 = 10 kN, F4 = 5
KN are acting on the sttructure shown. Determine the forces
in the members specified below. Use positive values to
indicate tension and negative values to indicate compression.
F2
D
b
F1
F3 C
E
b
F4
b
B
F
a
G
Values for dimensions on the figure are given in the following
table. Note the figure may not be to scale.
Variable Value
a
3 m
b
4 m
The force in member BC is
KN.
The force in member BE is
KN.
The force in member EF is
KN.
h
=
The transmission tower is subjected to the forces F₁ 3.6
KN at 50° and F2 = 3.3 kN at = 35°. Determine the
forces in members BC, BP, PQ, PC, CD, DP and NP.
Use positive values to indicate tension and negative values to
indicate compression.
不
кажаж в *а*аж
E
N
M
d
d
IF, c
B
CENTER
LINE
S
อ
K
F₂
Kbb
cc 10
BY NC SA
2013 Michael Swanbom
Values for dimensions on the figure are given in the following
table. Note the figure may not be to scale.
Variable
Value
a
1.7 m
b
4.9 m
с
3 m
d
5.2 m
h
8.4 m
Values for dimensions on the figure are given in the following
table. Note the figure may not be to scale.
Variable Value
a
1.7 m
4.9 m
с
3 m
d
5.2 m
h
8.4 m
The force in member BC is
KN.
The force in member BP is
KN.
The force in member PQ is
KN.
The force in member PC is
KN.
The force in member CD is
KN.
The force in member DP is
KN.
The force in member NP is
KN.
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