
(a)
Interpretation:
The chemical formula of sodium chromate has to be written.
(a)

Answer to Problem 22PE
The chemical formula of sodium chromate is
Explanation of Solution
In sodium chromate, the cation is sodium
The chemical formula of sodium chromate is
(b)
Interpretation:
The chemical formula of magnesium hydride has to be written.
(b)

Answer to Problem 22PE
The chemical formula of magnesium hydride is
Explanation of Solution
In magnesium hydride, the cation is magnesium
The chemical formula of magnesium hydride is
(c)
Interpretation:
The chemical formula of nickel (II) acetate has to be written.
(c)

Answer to Problem 22PE
The chemical formula of nickel (II) acetate is
Explanation of Solution
In nickel (II) acetate, the cation is nickel (II)
The chemical formula of nickel (II) acetate is
(d)
Interpretation:
The chemical formula of calcium chlorate has to be written.
(d)

Answer to Problem 22PE
The chemical formula of calcium chlorate is
Explanation of Solution
In calcium chlorate, the cation is calcium
The chemical formula of calcium chlorate is
(e)
Interpretation:
The chemical formula of magnesium bromate has to be written.
(e)

Answer to Problem 22PE
The chemical formula of magnesium bromate is
Explanation of Solution
In magnesium bromate, the cation is magnesium
The chemical formula of magnesium bromate is
(f)
Interpretation:
The chemical formula of potassium dihydrogen phosphate has to be written.
(f)

Answer to Problem 22PE
The chemical formula of potassium dihydrogen phosphate is
Explanation of Solution
In potassium dihydrogen phosphate, the cation is potassium
The chemical formula of potassium dihydrogen phosphate is
(g)
Interpretation:
The chemical formula of manganese (II) hydroxide has to be written.
(g)

Answer to Problem 22PE
The chemical formula of manganese (II) hydroxide is
Explanation of Solution
In manganese (II) hydroxide, the cation is manganese (II)
The chemical formula of manganese (II) hydroxide is
(h)
Interpretation:
The chemical formula of cobalt (II) hydrogen carbonate has to be written.
(h)

Answer to Problem 22PE
The chemical formula of cobalt (II) hydrogen carbonate is
Explanation of Solution
In cobalt (II) hydrogen carbonate, the cation is cobalt (II)
The chemical formula of cobalt (II) hydrogen carbonate is
(i)
Interpretation:
The chemical formula of sodium hypochlorite has to be written.
(i)

Answer to Problem 22PE
The chemical formula of sodium hypochlorite is
Explanation of Solution
In sodium hypochlorite, the cation is sodium
The chemical formula of sodium hypochlorite is
(j)
Interpretation:
The chemical formula of barium perchlorate has to be written.
(j)

Answer to Problem 22PE
The chemical formula of barium perchlorate is
Explanation of Solution
In barium perchlorate, the cation is barium
The chemical formula of barium perchlorate is
(k)
Interpretation:
The chemical formula of chromium (III) sulfite has to be written.
(k)

Answer to Problem 22PE
The chemical formula of chromium (III) sulfite is
Explanation of Solution
In chromium (III) sulfite, the cation is chromium (III)
The chemical formula of chromium (III) sulfite is
(l)
Interpretation:
The chemical formula of antimony (III) sulfate has to be written.
(l)

Answer to Problem 22PE
The chemical formula of antimony (III) sulfate is
Explanation of Solution
In antimony (III) sulfate, the cation is antimony (III)
The chemical formula of antimony (III) sulfate is
(m)
Interpretation:
The chemical formula of sodium oxalate has to be written.
(m)

Answer to Problem 22PE
The chemical formula of sodium oxalate is
Explanation of Solution
In sodium oxalate, the cation is sodium
The chemical formula of sodium oxalate is
(n)
Interpretation:
The chemical formula of potassium thiocyanate has to be written.
(n)

Answer to Problem 22PE
The chemical formula of potassium thiocyanate is
Explanation of Solution
In potassium thiocyanate, the cation is potassium
The chemical formula of potassium thiocyanate is
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Chapter 6 Solutions
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
- (2 pts) What do you expect to happen in a Na2O crystal if a Cl− ion replaces one of the O2−ions in the lattice?arrow_forward(2 pts) WSe2 is an ionic compound semiconductor that can be made to be p-type or n-type.What must happen to the chemical composition for it to be p-type? What must happen tothe chemical composition for it to be n-type?arrow_forward8. (2 pts) Silicon semiconductors have a bandgap of 1.11 eV. What is the longest photon wavelength that can promote an electron from the valence band to the conduction band in a silicon-based photovoltaic solar cell? Show all work. E = hv = hc/λ h = 6.626 x 10-34 Js c = 3.00 x 108 m/s 1 eV 1.602 x 10-19 Jarrow_forward
- A solution containing 100.0 mL of 0.155 M EDTA buffered to pH 10.00 was titrated with 100.0 mL of 0.0152 M Hg(ClO4)2 in a cell: calomel electrode (saturated)//titration solution/Hg(l) Given the formation constant of Hg(EDTA)2-, logKf= 21.5, and alphaY4-=0.30, find out the cell voltage E. Hg2+(aq) + 2e- = Hg(l) E0= 0.852 V E' (calomel electrode, saturated KCl) = 0.241 Varrow_forwardFrom the following reduction potentials I2 (s) + 2e- = 2I- (aq) E0= 0.535 V I2 (aq) + 2e- = 2I- (aq) E0= 0.620 V I3- (aq) + 2e- = 3I- (aq) E0= 0.535 V a) Calculate the equilibrium constant for I2 (aq) + I- (aq) = I3- (aq). b) Calculate the equilibrium constant for I2 (s) + I- (aq) = I3- (aq). c) Calculate the solubility of I2 (s) in water.arrow_forward2. (3 pts) Consider the unit cell for the spinel compound, CrFe204. How many total particles are in the unit cell? Also, show how the number of particles and their positions are consistent with the CrFe204 stoichiometry - this may or may not be reflected by the particle colors in the diagram. (HINT: In the diagram, the blue particle is in an interior position while each red particle is either in a corner or face position.)arrow_forward
- From the following potentials, calculate the activity of Cl- in saturated KCl. E0 (calomel electrode)= 0.268 V E (calomel electrode, saturated KCl)= 0.241 Varrow_forwardCalculate the voltage of each of the following cells. a) Fe(s)/Fe2+ (1.55 x 10-2 M)//Cu2+ (6.55 x 10-3 M)/Cu(s) b) Pt, H2 (0.255 bar)/HCl (4.55 x 10-4 M), AgCl (sat'd)/Ag Fe2+ +2e- = Fe E0= -0.44 V Cu2+ + 2e- = Cu E0= 0.337 V Ag+ + e- = Ag E0= 0.799 V AgCl(s) + e- = Ag(s) + Cl- E0= 0.222 V 2H+ + 2e- = H2 E0= 0.000 Varrow_forwardA solution contains 0.097 M Ce3+, 1.55x10-3 M Ce4+, 1.55x10-3 M Mn2+, 0.097 M MnO4-, and 1.00 M HClO4 (F= 9.649 x 104 C/mol). a) Write a balanced net reaction that can occur between species in this solution. b) Calculate deltaG0 and K for the reaction. c) Calculate E and deltaG for the conditions given. Ce4+ + e- = Ce3+ E0= 1.70 V MnO4- + 8H+ + 5e- = Mn2+ + 4H2O E0= 1.507 Varrow_forward
- 1. Provide a step-by-step mechanism for formation of ALL STEREOISOMERS in the following reaction. Na HCO3 (Sodium bicarbonate, baking soda) is not soluble in CH2Cl2. The powder is a weak base used to neutralize strong acid (pKa < 0) produced by the reaction. Redraw the product to show the configuration(s) that form at C-2 and C-4. Br2 OH CH2Cl2 Na* HCO3 Br HO OH + Na Br +arrow_forward2. Specify the solvent and reagent(s) required to carry out each of the following FGI. If two reagent sets must be used for the FGI, specify the solvent and reagent(s) for each reagent set. If a reaction cannot be carried out with reagents (sets) class, write NP (not possible) in the solvent box for reagent set #1. Use the letter abbreviation for each solvent; use a number abbreviation for reagent(s). Solvents: CH2Cl2 (A); H₂O (B); Reagents: HBr (1); R₂BH (6); H2SO4 (2); CH3OH (C); Br₂ (3); CH3CO₂H (D) NaHCO3 (4); Hg(OAc)2 (5); H₂O2/HO (7); NaBH4 (8) Reagent Set #1 Reagent Set #2 FGI + enant OH Solvent Reagent(s) Solvent Reagent(s)arrow_forwardGermanium (Ge) is a semiconductor with a bandgap of 2.2 eV. How could you dope Ge to make it a p-type semiconductor with a larger bandgap? Group of answer choices It is impossible to dope Ge and have this result in a larger bandgap. Dope the Ge with silicon (Si) Dope the Ge with gallium (Ga) Dope the Ge with phosphorus (P)arrow_forward
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning

