
(a)
Interpretation:
The chemical formula of silver sulfite has to be written.
(a)

Answer to Problem 21PE
The chemical formula of silver sulfite is
Explanation of Solution
In silver sulfite, the cation is silver (I)
The chemical formula of silver sulfite is
(b)
Interpretation:
The chemical formula of cobalt (II) bromide has to be written.
(b)

Answer to Problem 21PE
The chemical formula of cobalt (II) bromide is
Explanation of Solution
In cobalt (II) bromide, the cation is cobalt (II)
The chemical formula of cobalt (II) bromide is
(c)
Interpretation:
The chemical formula of tin (II) hydroxide has to be written.
(c)

Answer to Problem 21PE
The chemical formula of tin (II) hydroxide is
Explanation of Solution
In tin (II) hydroxide, the cation is tin (II)
The chemical formula of tin (II) hydroxide is
(d)
Interpretation:
The chemical formula of aluminum sulfate has to be written.
(d)

Answer to Problem 21PE
The chemical formula of aluminum sulfate is
Explanation of Solution
In aluminum sulfate, the cation is aluminum
The chemical formula of aluminum sulfate is
(e)
Interpretation:
The chemical formula of lead (II) chloride has to be written.
(e)

Answer to Problem 21PE
The chemical formula of lead (II) chloride is
Explanation of Solution
In lead (II) chloride, the cation is lead (II)
The chemical formula of lead (II) chloride is
(f)
Interpretation:
The chemical formula of ammonium carbonate has to be written.
(f)

Answer to Problem 21PE
The chemical formula of ammonium carbonate is
Explanation of Solution
In ammonium carbonate, the cation is ammonium
The chemical formula of ammonium carbonate is
(g)
Interpretation:
The chemical formula of chromium (III) oxide has to be written.
(g)

Answer to Problem 21PE
The chemical formula of chromium (III) oxide is
Explanation of Solution
In chromium (III) oxide, the cation is chromium (III)
The chemical formula of chromium (III) oxide is
(h)
Interpretation:
The chemical formula of copper (II) chloride has to be written.
(h)

Answer to Problem 21PE
The chemical formula of copper (II) chloride is
Explanation of Solution
In copper (II) chloride, the cation is copper (II)
The chemical formula of copper (II) chloride is
(i)
Interpretation:
The chemical formula of potassium permanganate has to be written.
(i)

Answer to Problem 21PE
The chemical formula of potassium permanganate is
Explanation of Solution
In potassium permanganate, the cation is potassium
The chemical formula of potassium permanganate is
(j)
Interpretation:
The chemical formula of arsenic (V) sulfite has to be written.
(j)

Answer to Problem 21PE
The chemical formula of arsenic (V) sulfite is
Explanation of Solution
In arsenic (V) sulfite, the cation is arsenic (V)
The chemical formula of arsenic (V) sulfite is
(k)
Interpretation:
The chemical formula of sodium peroxide has to be written.
(k)

Answer to Problem 21PE
The chemical formula of sodium peroxide is
Explanation of Solution
In sodium peroxide, the cation is sodium
The chemical formula of sodium peroxide is
(l)
Interpretation:
The chemical formula of iron (II) sulfate has to be written.
(l)

Answer to Problem 21PE
The chemical formula of iron (II) sulfate is
Explanation of Solution
In iron (II) sulfate, the cation is iron (II)
The chemical formula of iron (II) sulfate is
(m)
Interpretation:
The chemical formula of potassium dichromate has to be written.
(m)

Answer to Problem 21PE
The chemical formula of potassium dichromate is
Explanation of Solution
In potassium dichromate, the cation is potassium
The chemical formula of potassium dichromate is
(n)
Interpretation:
The chemical formula of bismuth (III) chromate has to be written.
(n)

Answer to Problem 21PE
The chemical formula of bismuth (III) chromate is
Explanation of Solution
In bismuth (III) chromate, the cation is bismuth (III)
The chemical formula of bismuth (III) chromate is
Want to see more full solutions like this?
Chapter 6 Solutions
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
- (2 pts) What do you expect to happen in a Na2O crystal if a Cl− ion replaces one of the O2−ions in the lattice?arrow_forward(2 pts) WSe2 is an ionic compound semiconductor that can be made to be p-type or n-type.What must happen to the chemical composition for it to be p-type? What must happen tothe chemical composition for it to be n-type?arrow_forward8. (2 pts) Silicon semiconductors have a bandgap of 1.11 eV. What is the longest photon wavelength that can promote an electron from the valence band to the conduction band in a silicon-based photovoltaic solar cell? Show all work. E = hv = hc/λ h = 6.626 x 10-34 Js c = 3.00 x 108 m/s 1 eV 1.602 x 10-19 Jarrow_forward
- A solution containing 100.0 mL of 0.155 M EDTA buffered to pH 10.00 was titrated with 100.0 mL of 0.0152 M Hg(ClO4)2 in a cell: calomel electrode (saturated)//titration solution/Hg(l) Given the formation constant of Hg(EDTA)2-, logKf= 21.5, and alphaY4-=0.30, find out the cell voltage E. Hg2+(aq) + 2e- = Hg(l) E0= 0.852 V E' (calomel electrode, saturated KCl) = 0.241 Varrow_forwardFrom the following reduction potentials I2 (s) + 2e- = 2I- (aq) E0= 0.535 V I2 (aq) + 2e- = 2I- (aq) E0= 0.620 V I3- (aq) + 2e- = 3I- (aq) E0= 0.535 V a) Calculate the equilibrium constant for I2 (aq) + I- (aq) = I3- (aq). b) Calculate the equilibrium constant for I2 (s) + I- (aq) = I3- (aq). c) Calculate the solubility of I2 (s) in water.arrow_forward2. (3 pts) Consider the unit cell for the spinel compound, CrFe204. How many total particles are in the unit cell? Also, show how the number of particles and their positions are consistent with the CrFe204 stoichiometry - this may or may not be reflected by the particle colors in the diagram. (HINT: In the diagram, the blue particle is in an interior position while each red particle is either in a corner or face position.)arrow_forward
- From the following potentials, calculate the activity of Cl- in saturated KCl. E0 (calomel electrode)= 0.268 V E (calomel electrode, saturated KCl)= 0.241 Varrow_forwardCalculate the voltage of each of the following cells. a) Fe(s)/Fe2+ (1.55 x 10-2 M)//Cu2+ (6.55 x 10-3 M)/Cu(s) b) Pt, H2 (0.255 bar)/HCl (4.55 x 10-4 M), AgCl (sat'd)/Ag Fe2+ +2e- = Fe E0= -0.44 V Cu2+ + 2e- = Cu E0= 0.337 V Ag+ + e- = Ag E0= 0.799 V AgCl(s) + e- = Ag(s) + Cl- E0= 0.222 V 2H+ + 2e- = H2 E0= 0.000 Varrow_forwardA solution contains 0.097 M Ce3+, 1.55x10-3 M Ce4+, 1.55x10-3 M Mn2+, 0.097 M MnO4-, and 1.00 M HClO4 (F= 9.649 x 104 C/mol). a) Write a balanced net reaction that can occur between species in this solution. b) Calculate deltaG0 and K for the reaction. c) Calculate E and deltaG for the conditions given. Ce4+ + e- = Ce3+ E0= 1.70 V MnO4- + 8H+ + 5e- = Mn2+ + 4H2O E0= 1.507 Varrow_forward
- 1. Provide a step-by-step mechanism for formation of ALL STEREOISOMERS in the following reaction. Na HCO3 (Sodium bicarbonate, baking soda) is not soluble in CH2Cl2. The powder is a weak base used to neutralize strong acid (pKa < 0) produced by the reaction. Redraw the product to show the configuration(s) that form at C-2 and C-4. Br2 OH CH2Cl2 Na* HCO3 Br HO OH + Na Br +arrow_forward2. Specify the solvent and reagent(s) required to carry out each of the following FGI. If two reagent sets must be used for the FGI, specify the solvent and reagent(s) for each reagent set. If a reaction cannot be carried out with reagents (sets) class, write NP (not possible) in the solvent box for reagent set #1. Use the letter abbreviation for each solvent; use a number abbreviation for reagent(s). Solvents: CH2Cl2 (A); H₂O (B); Reagents: HBr (1); R₂BH (6); H2SO4 (2); CH3OH (C); Br₂ (3); CH3CO₂H (D) NaHCO3 (4); Hg(OAc)2 (5); H₂O2/HO (7); NaBH4 (8) Reagent Set #1 Reagent Set #2 FGI + enant OH Solvent Reagent(s) Solvent Reagent(s)arrow_forwardGermanium (Ge) is a semiconductor with a bandgap of 2.2 eV. How could you dope Ge to make it a p-type semiconductor with a larger bandgap? Group of answer choices It is impossible to dope Ge and have this result in a larger bandgap. Dope the Ge with silicon (Si) Dope the Ge with gallium (Ga) Dope the Ge with phosphorus (P)arrow_forward
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
- Living By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHERIntroduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co




