A nine-laboratory cooperative study was performed to evaluate quality control for susceptibility tests with 30-μg netilmicin disks [6]. Each laboratory tested three standard control strains on a different lot of Mueller-Hinton agar, with 150 tests performed per laboratory. For protocol control, each laboratory also performed 15 additional tests on each of the control strains using the same lot of Mueller-Hinton agar across laboratories. The mean zone diameters for each of the nine laboratories are given in Table 6.11.
Are there any advantages to using a common medium versus using different media for performing the susceptibility tests with regard to standardization of results across laboratories?
Table 6.11 Mean zone diameters with 30-μg netilmicin disks tested in nine separate laboratories
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Chapter 6 Solutions
Fundamentals of Biostatistics
- Five samples of a ferrous-type substance were used to determine if there is a difference between a laboratory chemical analysis and an X-ray fluorescence analysis of the iron content. Each sample was split into two subsamples and the two types of analysis were applied, with the accompanying results. Assuming that the populations are normal, test at the 0.02 level of significance whether the two methods of analysis give, on the average, the same resultarrow_forwardFive samples of a ferrous-type substance were used to determine if there is a difference between a laboratory chemical analysis and an X-ray fluorescence analysis of the iron content. Each sample was split into two subsamples and the two types of analysis were applied, with the accompanying results. Assuming that the populations are normal, test at the 0.05 level of significance whether the two methods of analysis give, on the average, the same result. Determine the test statistic t=?arrow_forwardIn some mining operations, a byproduct of the processing is mildly radioactive and release of these byproducts into the environment may contaminate the freshwater supply. There are strict regulations for the maximum allowable radioactivity in supplies of drinking water, namely an average of 5 picocuries per litre (pCi/L) or less. A random sample of 40 specimens of water from the city’s water supply gave a mean of 5.39 pCi/L and a standard deviation of 0.77 pCi/L. Is the city’s water supply contaminated? Test this hypothesis at the 0.01 level of significance. Give an approximate p-value for the test statistic.arrow_forward
- Three different methods for assembling a product were proposed by an industrial engineer. To investigate the number of units assembled correctly with each method, 30 employees were randomly selected and randomly assigned to the three proposed methods in such a way that each method was used by10 workers. The number of units assembled correctly was recorded, and the analysis of variance procedure was applied to the resulting data set. The following results were obtained: ; . SST:10,700 SSTR:4500 a. Set up the ANOVA table for this problem (to 2 decimals, if necessary). Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value (to 4 decimals) Treatments…arrow_forwardMendel counted 4000 peas from a dihybrid cross and predicted a 9:3:3:1 phenotypic ratio with the following results. Yellow and smooth peas 2100; yellow and wrinkled peas 700: green and smooth peas 859 and green and wrinkled peas 341. Support or refute these data with a CHI-Square analysis. State the Null hypothesis and its outcome for this set of data.arrow_forwardThree different methods for assembling a product were proposed by an industrial engineer. To investigate the number of units assembled correctly with each method, 30 employees were randomly selected and randomly assigned to the three proposed methods in such a way that each method was used by 10 workers. The number of units assembled correctly was recorded, and the analysis of variance procedure was applied to the resulting data set. The following results were obtained: SST =10,890; SSTR =4600. a. Set up the ANOVA table for this problem (to 2 decimals but p-value to 4 decimals, if necessary). Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments Error Total b.Use a 0.05 to test for any significant difference in the means for the three assembly methods. %3D Calculate the value of the test statistic (to 2 decimals). The p-value is - Select your answer - What is your conclusion? - Select your answer -arrow_forward
- A wine enthusiast named Suds collected data on the alc content (percent by volume) of wine for one grape variety in 2012 by a random sample of winemakers in Italy. Suds created the following Table: Alcohol % Mean 13.093 Std Error 0.1143 Median 13.165 Mode 13.17 Std Deviation 0.5111 Sample Variance 0.2612 Kurtosis -0.8385 Skew -0.1747 Range 1.68 Minimum 12.2 Maximum 13.88 Sum 261.86 Count 20 Use the table to determine whether mean alc content of all wines for that grape in 2012 in Italy was greater than 12.75% at the 0.1 significance. a) State the null and alternaternative hypothesis. b) What is the calculated value of the associated test statistic and what is the critical value of the associated test statistic? c) State your decision about the null hypothesis by comparing calculated and critical values of the statistic. State your conclusion(describe what the decision means in this problem).arrow_forwardThe dry shear strength of birch plywood bonded with different resin glues was st- udied with a completely randomized desig- ned experiment. Here are the data: Glue A (102; 58; 45; 79; 68; 63; 117) Glue C (100; 102; 80; 119) Glue F (220; 243; 189; 176; 176). SSE = 8167.55; MSE = 628.27; and F stat = 37.99. What inference can be made?arrow_forwardPatients with rheumatoid arthritis are at a greater risk of developing osteoporosis. The reasons are not well understood due to the difficulty in qualitatively assessing bone metabolism and mineral content. A researcher measures human calcitonin (HCT) levels in men with rheumatoidarthritis. The researcher randomly selects 43 men with rheumatoid arthritis and measured the mean HCT level of 33.8 pg/mL. Assume that HCT for individuals with rheumatoid arthritis follows a normal distribution with standard deviation σ = 23.6 pg/mL. 7. Describe a situation where a researcher would want to use a larger confidence level than 95% and a situation where a smaller confidence level would be preferred.arrow_forward
- Patients with rheumatoid arthritis are at a greater risk of developing osteoporosis. The reasons are not well understood due to the difficulty in qualitatively assessing bone metabolism and mineral content. A researcher measures human calcitonin (HCT) levels in men with rheumatoidarthritis. The researcher randomly selects 43 men with rheumatoid arthritis and measured the mean HCT level of 33.8 pg/mL. Assume that HCT for individuals with rheumatoid arthritis follows a normal distribution with standard deviation σ = 23.6 pg/mL. 4. Explain in detail what the 95% Confidence Interval for the mean HCT represents within this context.arrow_forwardThree different methods for assembling a product were proposed by an industrial engineer. To investigate the number of units assembled correctly with each method, 30 employees were randomly selected and randomly assigned to the three proposed methods in such a way that each method was used by 10 workers. The number of units assembled correctly was recorded, and the analysis of variance procedure was applied to the resulting data set. The following results were obtained: SST =10,790; SSTR =4520. a. Set up the ANOVA table for this problem (to 2 decimals but p-value to 4 decimals, if necessary). Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments Error Total b.Use a = 0.05 to test for any significant difference in the means for the three assembly methods. Calculate the value of the test statistic (to 2 decimals). The p-value is -sSelect your answer - What is your conclusion? - Select your answer - 00 00arrow_forwardAn experiment is conducted at the significance level of 0.005 to determine whether there is a difference among the mean increases in growth produced by five strains (A, B, C, D and E) of growth hormones for plants. The experimental material consists of 20 cuttings of a shrub (all of equal weight), with four cuttings randomly assigned to each of the five different strains. The increases in weight for each cutting along with the sample mean and sample standard deviation of each group are given in the table below. A B DE Plant 1 16 23 25 10 9 Plant 2 12 29 23 19 14 Plant 3 11 28 22 19 6 Plant 4 17 24 20 13 6 Σχ 56 104 90 61 35 Ex? 810 2730 2038 991 349 Compute the following: (a) SST= (b) SSE = (c) MST = (d) MSE = (e) F = (f) The rejection region is:arrow_forward
- Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill