Chapter 6, Problem 21RE

Explanation of Solution

a. The given code:

// creating variable s and initializing by “1”.

int s = 1;

// iterate the for loop up to “n<=5”.

for (int n = 1; n <= 5; n++)

{

    // variable “s” is added with value of “n”

    s = s + n;

    //prompting the value of “s”

    System.out.print(s + " ");

}

Explanation:

The above snippet of code is used to demonstrate “for” loop. In the code,

• An integer variable “s” is created and assigned a value “1”.
• Iterate “for” loop up to the condition “n <= 5”. The loop variable was initialized with “n=1” and every iteration “n” is incremented by “1”.
  • The variable “s” is added with value of “n”.
  • The value of “s” is printed on the screen.

Trace table for the code snippet:

s = 1 + 1 = 2

s = 2 + 2 = 4

s = 4+ 3 = 7

s = 7+ 4 = 11

s = 11 +5 = 16

Expected output:

2 4 7 11 16

b. The given code:

// creating variable s and initializing by “1”.

int s = 1;

// iterate the for loop up to “s<=10”.

for (int n = 1; s <= 10;System.out.print(s + " "))

{

    //loop variable n is added with 2

    n = n + 2;

/*variable “s” added with value of “n” and the value is assigned to s*/

    s = s + n;

}

Explanation:

The above snippet of code is used to demonstrate “for” loop. In the code,

• An integer variable “s” is created and assigned a value “1”.
  • Iterate “for” loop up to the condition “s <= 10”...