Introduction To General, Organic, And Biochemistry
Introduction To General, Organic, And Biochemistry
12th Edition
ISBN: 9781337571357
Author: Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher: Cengage Learning
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Chapter 6, Problem 21P

6-35 Describe how we would prepare the following solutions:

(a) 280. mL of a 27% v/v solution of ethanol C2H6O, in water

(b) 435 mL of a 1.8% v/v solution of ethyl acetate, C4H8O2 in water

(c) 1.65 L of an 8.00% v/v solution of benzene C6H6, in chloroform, CHCI3

(a)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The formation of following solutions should be explained:

280.0 mL of a 27% v/v solution of ethanol, C2H6O in water.

Concept Introduction:

Concentration has several ways to be calculated. It typically relates an amount of solute and the solution. In volume of solute per unit volume of solvent, or v/v, the total volume of the solute, solvent and solution must be known.

The formula for v/v is as follows:

Cv/v=VsoluteVsolvent×100%.

Here, Vsolute is volume of solute and Vsolvent is volume of solvent.

When solving for the required volume of solute, the following formula is used:

Cv/v=VsoluteVsolute+Vsolvent×100%.

Answer to Problem 21P

75.6 mL of the solute must be added.

Explanation of Solution

Given:

V=280.0 mLC=27%v/v.

The formula for v/v is as follows:

Cv/v=VsoluteVsolvent×100%.

Here, Vsolute is volume of solute and Vsolvent is volume of solvent.

When solving for the required volume of solute, the following formula is used:

Cv/v=VsoluteVsolute+Vsolvent×100%.

Substitute known data and solve for mass of solute.

Cv/v=VsoluteVsolute+Vsolvent×100%27%v/v=Vsolute280 mL×100%Vsolute=27%v/v100%(280 mL)Vsolute=75.6 mL

Thus, add 75.6 mL of solute and then add the remaining volume of water.

(b)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The formation of following solutions should be explained:

435 mL of a 1.8 % v/v solution of ethyl acetate C4H8O2 in water.

Concept Introduction:

Concentration has several ways to be calculated. It typically relates an amount of solute and the solution. In volume of solute per unit volume of solvent, or v/v, the total volume of the solute, solvent and solution must be known.

The formula for v/v is as follows:

Cv/v=VsoluteVsolvent×100%.

Here, Vsolute is volume of solute and Vsolvent is volume of solvent.

When solving for the required volume of solute, the following formula is used:

Cv/v=VsoluteVsolute+Vsolvent×100%.

Answer to Problem 21P

7.83mL of the solute must be added.

Explanation of Solution

Given:

V=435mLC=1.8%v/v.

The formula for v/v is as follows:

Cv/v=VsoluteVsolvent×100%.

Here, Vsolute is volume of solute and Vsolvent is volume of solvent.

When solving for the required volume of solute, the following formula is used:

Cv/v=VsoluteVsolute+Vsolvent×100%.

Substitute known data and solve for mass of solute.

Cv/v=VsoluteVsolute+VsolventX100%1.8%v/v=Vsolute435 mL×100%Vsolute=1.8%v/v100%(435mL)Vsolute=7.83 mL

Then, add 7.83 mL volume of solute to the remaining volume of water.

(b)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The formation of following solutions should be explained:

1.65 L of a 8.00 % v/v solution of benzene, C6H6 in chloroform, CHCl3.

Concept Introduction:

Concentration has several ways to be calculated. It typically relates an amount of solute and the solution. In volume of solute per unit volume of solvent, or v/v, the total volume of the solute, solvent and solution must be known.

The formula for v/v is as follows:

Cv/v=VsoluteVsolvent×100%.

Here, Vsolute is volume of solute and Vsolvent is volume of solvent.

When solving for the required volume of solute, the following formula is used:

Cv/v=VsoluteVsolute+Vsolvent×100%.

Answer to Problem 21P

132 mL of the solute must be added.

Explanation of Solution

Given:

V=1.65L=1650mLC=8.00%v/v.

The formula for v/v is as follows:

Cv/v=VsoluteVsolvent×100%.

Here, Vsolute is volume of solute and Vsolvent is volume of solvent.

When solving for the required volume of solute, the following formula is used:

Cv/v=VsoluteVsolute+Vsolvent×100%.

Substitute known data and solve for mass of solute.

Cv/v=VsoluteVsolute+Vsolvent×100%8.00%v/v=Vsolute1650mL×100%Vsolute=8.0%v/v100%(1650 mL)Vsolute=132 mL

Then, add 132 mL of solute is added to the remaining volume of water.

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Chapter 6 Solutions

Introduction To General, Organic, And Biochemistry

Ch. 6.8 - Prob. 6.11QCCh. 6.8 - Prob. 6.12QCCh. 6.8 - Problem 6-13 What is the osmolarity of a 3.3% w/v...Ch. 6.8 - Prob. 6.14QCCh. 6 - 6-15 Answer true or false. (a) A solute is the...Ch. 6 - 6-16 Answer true or false. (a) Solubility is a...Ch. 6 - 6-17 Vinegar is a homogeneous aqueous solution...Ch. 6 - 6-18 Suppose you prepare a solution by dissolving...Ch. 6 - 6-19 In each of the following, tell whether the...Ch. 6 - 6-20 Give a familiar example of solutions of each...Ch. 6 - 6-21 Are mixtures of gases true solutions or...Ch. 6 - 6-22 Answer true or false. (a) Water is a good...Ch. 6 - 6-23 We dissolved 0.32 g of aspartic acid in 115.0...Ch. 6 - Prob. 10PCh. 6 - 6-25 A small amount of solid is added to a...Ch. 6 - 6-26 On the basis of polarity and hydrogen...Ch. 6 - Prob. 13PCh. 6 - 6-28 Which pairs of liquids are likely to be...Ch. 6 - Prob. 15PCh. 6 - 6-30 Near a power plant, warm water is discharged...Ch. 6 - 6-31 If a bottle of beer is allowed to stand for...Ch. 6 - 6-32 Would you expect the solubility of ammonia...Ch. 6 - Prob. 19PCh. 6 - Prob. 20PCh. 6 - 6-35 Describe how we would prepare the following...Ch. 6 - Prob. 22PCh. 6 - 6-37 Calculate the w/v percentage of each of these...Ch. 6 - 6-38 Describe how we would prepare 250 mL of 0.10...Ch. 6 - 6-39 Assuming that the appropriate volumetric...Ch. 6 - 6-40 What is the molarity of each solution? (a) 47...Ch. 6 - 6-41 A teardrop with a volume of 0.5 mL contains...Ch. 6 - Prob. 28PCh. 6 - 6-43 The label on a sparkling cider says it...Ch. 6 - Prob. 30PCh. 6 - 6-45 The label on ajar of jam says it contains 13...Ch. 6 - 6-46 A particular toothpaste contains 0.17 g NaF...Ch. 6 - 6-47 A student has a bottle labeled 0.750% albumin...Ch. 6 - 6-48 How many grams of solute are present in each...Ch. 6 - 6-49 A student has a stock solution of 30.0% w/v...Ch. 6 - Prob. 36PCh. 6 - Prob. 37PCh. 6 - Prob. 38PCh. 6 - 6-53 Dioxin is considered to be poisonous in...Ch. 6 - 6-54 An industrial wastewater contains 3.60 ppb...Ch. 6 - 6-55 According to the label on a piece of cheese,...Ch. 6 - Prob. 42PCh. 6 - Prob. 43PCh. 6 - Prob. 44PCh. 6 - Prob. 45PCh. 6 - 6-60 Predict which of these covalent compounds is...Ch. 6 - On the basis of Tables 6.1 and 6.2 , classify the...Ch. 6 - Prob. 48PCh. 6 - Prob. 49PCh. 6 - Prob. 50PCh. 6 - 6-67 Calculate the freezing points of solutions...Ch. 6 - 6-68 If we add 175 g of ethylene glycol, C2H6O2,...Ch. 6 - Prob. 53PCh. 6 - 6-70 In winter, after a snowstorm, salt (NaCI) is...Ch. 6 - 6-71 A 4 M acetic acid (CH3COOH) solution lowers...Ch. 6 - Prob. 56PCh. 6 - 6-73 In each case, tell which side (if either)...Ch. 6 - 6-74 An osmotic semipermeable membrane that allows...Ch. 6 - 6-75 Calculate the osmolarity of each of the...Ch. 6 - Prob. 60PCh. 6 - Prob. 61PCh. 6 - Prob. 62PCh. 6 - Prob. 63PCh. 6 - Prob. 64PCh. 6 - Prob. 65PCh. 6 - 6-78 (Chemical Connections 6A) Oxides of nitrogen...Ch. 6 - Prob. 67PCh. 6 - Prob. 68PCh. 6 - Prob. 69PCh. 6 - 6-82 (Chemical Connections 6C) A solution contains...Ch. 6 - 6-83 (Chemical Connections 6C) The concentration...Ch. 6 - 6-84 (Chemical Connections 6D) What is the...Ch. 6 - Prob. 73PCh. 6 - Prob. 74PCh. 6 - Prob. 75PCh. 6 - Prob. 76PCh. 6 - Prob. 77PCh. 6 - Prob. 78PCh. 6 - 6-91 When a cucumber is put into a saline solution...Ch. 6 - Prob. 80PCh. 6 - 6-93 Two bottles of water are carbonated, with CO2...Ch. 6 - Prob. 82PCh. 6 - Prob. 83PCh. 6 - 6-96 We know that a 0.89% saline (NaCI) solution...Ch. 6 - Prob. 85PCh. 6 - Prob. 86PCh. 6 - 6-99 A concentrated nitric acid solution contains...Ch. 6 - 6-100 Which will have greater osmotic pressure?...Ch. 6 - Prob. 89PCh. 6 - Prob. 90PCh. 6 - 6-103 A swimming pool containing 20,000. L of...Ch. 6 - Prob. 92PCh. 6 - Prob. 93PCh. 6 - Prob. 94PCh. 6 - Prob. 95PCh. 6 - Prob. 96PCh. 6 - Prob. 97PCh. 6 - Prob. 98PCh. 6 - 6-111 As noted in Section 6-8C, the amount of...Ch. 6 - 6-112 List the following aqueous solutions in...Ch. 6 - 6-113 List the following aqueous solutions in...Ch. 6 - Prob. 102P
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY