Chapter 6, Problem 21E

To determine

To find newminimum, median, standard deviation and IQR.

Answer to Problem 21E

New values are:

Min = 372

Median = 436

Standard deviation = 33.60

IQR = 40.80

Explanation of Solution

Given:

Min = 980

Median = 1140

Standard deviation = 84

IQR = 102

All the values multiplied by 1.609.

  $\begin{array}{l}Min=\text{ 0}\text{.40}\times 980=372\hfill \\ Median=\text{ 0}\text{.40}\times 1140=436\hfill \\ Standarddeviation=\text{ 0}\text{.40}\times 84=33.60\hfill \\ IQR=\text{ 0}\text{.40}\times 102=40.80\hfill \end{array}$