EBK INTRODUCTORY CHEMISTRY: AN ACTIVE L
EBK INTRODUCTORY CHEMISTRY: AN ACTIVE L
6th Edition
ISBN: 9780100547506
Author: CRACOLICE
Publisher: YUZU
bartleby

Videos

Textbook Question
Book Icon
Chapter 6, Problem 1E

Review of Selected Concepts Related to Nomenclature

Write the chemical formula of each of the following. The blue spheres represent nitrogen atoms and the red spheres oxygen atoms. Oxygen is written last in the formulas that include oxygen.

Chapter 6, Problem 1E, Review of Selected Concepts Related to Nomenclature Write the chemical formula of each of the

Expert Solution
Check Mark
Interpretation Introduction

(a)

Interpretation:

The chemical formula of each of the following is to be written. The blue spheres represent nitrogen atoms and the red spheres oxygen atoms. Oxygen is written last in the formulas that include oxygen.

Concept introduction:

The particle of an element or compound in the written format is denoted by the chemical formulas. The symbols of elements in a particular substance covers the formula of the required substance.

Answer to Problem 1E

The chemical formula of (a) is written as N2

Explanation of Solution

Generally, in a formula, the total number of atoms of the element under study is shown by a subscript number immediately following the symbol. Notably, the subscript does not have the number when only one atom of an element present in the formula. The number of each kind of atom which makes up the particle generally called as the composition, is denoted by the chemical formula. Commonly, elements can be madeup of molecules having single atom, two atoms or complex multi-atoms. Coversely, when the substance itself is an element it should have all atoms of the same element. In the above example (a), the two lobes are having the same blue color which is for the element nitrogen.

Total number of lobes of nitrogen (N) = 2

Chemical formula = N2

Conclusion

Thus, the chemical formula of the colored lobes (a) is written.

Expert Solution
Check Mark
Interpretation Introduction

(b)

Interpretation:

The chemical formula of each of the following is to be written. The blue spheres represent nitrogen atoms and the red spheres oxygen atoms. Oxygen is written last in the formulas that include oxygen.

Concept introduction:

The particle of an element or compound in the written format is denoted by the chemical formulas. The symbols of elements in a particular substance covers the formula of the required substance.

Answer to Problem 1E

The chemical formula of (b) is written as NO2

Explanation of Solution

Generally, in a formula, the total number of atoms of the element under study is shown by a subscript number immediately following the symbol. Notably, the subscript does not have the number when only one atom of an element present in the formula. In the above example (b), the two lobes are having the same color which is for the element oxygen and one lobe is having the color for nitrogen.

Total number of lobes of nitrogen (N) = 1

Total number of lobes of oxygen (O) = 2

Chemical formula = NO2

Conclusion

Thus, the chemical formula of the colored lobes (b) is written.

Expert Solution
Check Mark
Interpretation Introduction

(c)

Interpretation:

The chemical formula of each of the following is to be written. The blue spheres represent nitrogen atoms and the red spheres oxygen atoms. Oxygen is written last in the formulas that include oxygen.

Concept introduction:

The particle of an element or compound in the written format is denoted by the chemical formulas. The symbols of elements in a particular substance covers the formula of the required substance.

Answer to Problem 1E

The chemical formula of (c) is written as N2O

Explanation of Solution

Generally, in a formula, the total number of atoms of the element under study is shown by a subscript number immediately following the symbol. Notably, the subscript does not have the number when only one atom of an element present in the formula. In the above example (c), the two lobes are having the same color which is for the element nitrogen and one lobe is having the color for oxygen.

Total number of lobes of nitrogen (N) = 2

Total number of lobes of oxygen (O) = 1

Chemical formula = N2O

Conclusion

Thus, the chemical formula of the colored lobes (c) is written.

Expert Solution
Check Mark
Interpretation Introduction

(d)

Interpretation:

The chemical formula of each of the following is to be written. The blue spheres represent nitrogen atoms and the red spheres oxygen atoms. Oxygen is written last in the formulas that include oxygen.

Concept introduction:

The particle of an element or compound in the written format is denoted by the chemical formulas. The symbols of elements in a particular substance covers the formula of the required substance.

Answer to Problem 1E

The chemical formula of (d) is written as N2O4

Explanation of Solution

Generally, in a formula, the total number of atoms of the element under study is shown by a subscript number immediately following the symbol. Notably, the subscript does not have the number when only one atom of an element present in the formula. In the above example (d), the two lobes are having the same color which is for the element nitrogen and other four lobes are having the color for oxygen.

Total number of lobes of nitrogen (N) = 2

Total number of lobes of oxygen (O) = 4

Chemical formula = N2O4

Conclusion

Thus, the chemical formula of the colored lobes (d) is written.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Please don't use Ai solution
None
dont provide AI solution.....

Chapter 6 Solutions

EBK INTRODUCTORY CHEMISTRY: AN ACTIVE L

Ch. 6 - Prob. 11ECh. 6 - Prob. 12ECh. 6 - Prob. 13ECh. 6 - CCl4, CBr4, NO, dinitrogen monoxide, sulfur...Ch. 6 - Prob. 15ECh. 6 - Write an equation that shows the formation of a...Ch. 6 - Prob. 17ECh. 6 - Prob. 18ECh. 6 - Prob. 19ECh. 6 - Prob. 20ECh. 6 - Prob. 21ECh. 6 - Prob. 22ECh. 6 - What are the names of AgBr, SnF2, Fe2O3, and...Ch. 6 - Prob. 24ECh. 6 - Prob. 25ECh. 6 - Prob. 26ECh. 6 - Prob. 27ECh. 6 - Prob. 28ECh. 6 - Prob. 29ECh. 6 - Fill in the blanks in the following table....Ch. 6 - Prob. 31ECh. 6 - Prob. 32ECh. 6 - What is the formula of sodium tellurate; what are...Ch. 6 - Prob. 34ECh. 6 - Explain how an anion can behave like an acid. Is...Ch. 6 - Prob. 36ECh. 6 - Prob. 37ECh. 6 - Prob. 38ECh. 6 - Prob. 39ECh. 6 - Prob. 40ECh. 6 - Among the following, identify all hydrates and...Ch. 6 - Prob. 42ECh. 6 - Prob. 43ECh. 6 - Prob. 44ECh. 6 - Prob. 45ECh. 6 - Prob. 46ECh. 6 - Prob. 47ECh. 6 - Prob. 48ECh. 6 - Prob. 49ECh. 6 - Prob. 50ECh. 6 - Prob. 51ECh. 6 - Prob. 52ECh. 6 - Prob. 53ECh. 6 - In each box, write the chemical formula of the...Ch. 6 - Prob. 55ECh. 6 - Prob. 56ECh. 6 - Prob. 57ECh. 6 - Prob. 58ECh. 6 - Prob. 59ECh. 6 - Prob. 60ECh. 6 - Prob. 61ECh. 6 - Prob. 62ECh. 6 - Prob. 63ECh. 6 - Prob. 64ECh. 6 - Prob. 65ECh. 6 - Prob. 66ECh. 6 - Prob. 67ECh. 6 - Prob. 68ECh. 6 - Prob. 69ECh. 6 - Prob. 70ECh. 6 - Prob. 71ECh. 6 - Prob. 72ECh. 6 - Prob. 73ECh. 6 - Prob. 74ECh. 6 - Prob. 75ECh. 6 - Prob. 76ECh. 6 - Prob. 77ECh. 6 - Prob. 78ECh. 6 - Prob. 79ECh. 6 - Prob. 80ECh. 6 - Prob. 81ECh. 6 - Prob. 82ECh. 6 - Prob. 83ECh. 6 - Prob. 84ECh. 6 - Prob. 85ECh. 6 - Prob. 86ECh. 6 - Prob. 1CLECh. 6 - Prob. 2CLECh. 6 - Prob. 3CLECh. 6 - Prob. 4CLECh. 6 - Prob. 1PECh. 6 - Prob. 2PECh. 6 - Prob. 3PECh. 6 - Prob. 4PECh. 6 - Prob. 5PECh. 6 - Prob. 6PECh. 6 - Prob. 7PECh. 6 - Prob. 8PECh. 6 - Prob. 9PECh. 6 - Prob. 10PECh. 6 - Prob. 11PECh. 6 - Prob. 12PECh. 6 - Prob. 13PECh. 6 - Prob. 14PECh. 6 - Prob. 15PECh. 6 - Prob. 16PECh. 6 - Prob. 17PE
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
  • Text book image
    Introductory Chemistry: A Foundation
    Chemistry
    ISBN:9781337399425
    Author:Steven S. Zumdahl, Donald J. DeCoste
    Publisher:Cengage Learning
    Text book image
    Chemistry: An Atoms First Approach
    Chemistry
    ISBN:9781305079243
    Author:Steven S. Zumdahl, Susan A. Zumdahl
    Publisher:Cengage Learning
    Text book image
    World of Chemistry, 3rd edition
    Chemistry
    ISBN:9781133109655
    Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
    Publisher:Brooks / Cole / Cengage Learning
  • Text book image
    Chemistry
    Chemistry
    ISBN:9781305957404
    Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
    Publisher:Cengage Learning
    Text book image
    Chemistry
    Chemistry
    ISBN:9781133611097
    Author:Steven S. Zumdahl
    Publisher:Cengage Learning
    Text book image
    Chemistry: Principles and Practice
    Chemistry
    ISBN:9780534420123
    Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
    Publisher:Cengage Learning
Text book image
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning
Text book image
World of Chemistry, 3rd edition
Chemistry
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Brooks / Cole / Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781133611097
Author:Steven S. Zumdahl
Publisher:Cengage Learning
Text book image
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
GCSE Chemistry - Differences Between Compounds, Molecules & Mixtures #3; Author: Cognito;https://www.youtube.com/watch?v=jBDr0mHyc5M;License: Standard YouTube License, CC-BY