Using MIS (9th Edition)
9th Edition
ISBN: 9780134106786
Author: David M. Kroenke, Randall J. Boyle
Publisher: PEARSON
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Expert Solution & Answer
Chapter 5.8, Problem 2ARQ
Explanation of Solution
Database is a collection of information that is used to store and retrieve the data. Data is organized in tables.
Hierarchy of Data:
The hierarchy of data is specified in tree-like structure. The records are connected through links. The database elements are,
- Table or File
- Records or Rows
- Fields or Columns
- Bytes or Characters
Metadata:
Metadata gives information about other data or simply, it is a data about the data.
- It provides the description about the characteristics or properties of end user data and environment of the data.
- The environment includes the source of the data, where it is stored, usage, and so on.
- It gives all the information about a data.
Relationship among the rows:
- Using the examples of “student” and the “office_visit” tables the relationship can be described as one to one relationship.
- Because the student number in the “student” table and the student number in the “office_visit” table have the unique student number.
- If any modification is made concerning the student number in the “student” table, then it is automatically updated in the “office_visit” table...
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Methods (Ch6) - Review
1. (The MyRoot method) Below is a manual implementation of the Math.sqrt() method in Java.
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public class SquareRoot {
public static void main(String[] args) {
}
// implement a loop of your choice here
// Method that calculates the square root of integer variables
public static double myRoot(int number) {
double root;
root=number/2;
double root old;
do {
root old root;
root (root_old+number/root_old)/2;
} while (Math.abs(root_old-root)>1.8E-6);
return root;
}
// Method that calculates the square root of double variables
public static double myRoot(double number) {
double root;
root number/2;
double root_old;
do {
root old root;
root (root_old+number/root_old)/2;
while (Math.abs (root_old-root)>1.0E-6);
return root;
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Chapter 5 Solutions
Using MIS (9th Edition)
Ch. 5.2 - Prob. 1EGDQCh. 5.2 - Prob. 2EGDQCh. 5.2 - Prob. 3EGDQCh. 5.2 - Prob. 4EGDQCh. 5.2 - Prob. 5EGDQCh. 5.2 - Prob. 6EGDQCh. 5.2 - Prob. 7EGDQCh. 5.2 - Prob. 8EGDQCh. 5.3 - Prob. 1NWDSCh. 5.3 - Prob. 2NWDS
Ch. 5.3 - Prob. 3NWDSCh. 5.3 - Prob. 4NWDSCh. 5.3 - Prob. 5NWDSCh. 5.8 - Prob. 1SGDQCh. 5.8 - Prob. 2SGDQCh. 5.8 - Prob. 3SGDQCh. 5.8 - Prob. 4SGDQCh. 5.8 - Prob. 5SGDQCh. 5.8 - Prob. 6SGDQCh. 5.8 - Prob. 7SGDQCh. 5.8 - Prob. 1IKDMCh. 5.8 - Prob. 2IKDMCh. 5.8 - Prob. 3IKDMCh. 5.8 - Prob. 4IKDMCh. 5.8 - Prob. 1ARQCh. 5.8 - Prob. 2ARQCh. 5.8 - Prob. 3ARQCh. 5.8 - Prob. 4ARQCh. 5.8 - Prob. 5ARQCh. 5.8 - Prob. 6ARQCh. 5.8 - Prob. 7ARQCh. 5.8 - Prob. 8ARQCh. 5 - Prob. 5.1UYKCh. 5 - Prob. 5.2UYKCh. 5 - Prob. 5.3UYKCh. 5 - Prob. 5.4UYKCh. 5 - Prob. 5.5CE5Ch. 5 - Prob. 5.6CE5Ch. 5 - Prob. 5.7CE5Ch. 5 - Prob. 5.8CE5Ch. 5 - Prob. 5.9CE5Ch. 5 - Prob. 5.10CE5Ch. 5 - Prob. 5.11CE5Ch. 5 - Prob. 5.12CE5Ch. 5 - Prob. 5.13CS5Ch. 5 - Prob. 5.14CS5Ch. 5 - Prob. 5.15CS5Ch. 5 - Prob. 5.16CS5Ch. 5 - Prob. 5.17CS5Ch. 5 - Prob. 5.18CS5Ch. 5 - Prob. 5.19CS5Ch. 5 - Prob. 5.2MMLCh. 5 - Prob. 5.21MML
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