Using MIS (9th Edition)
9th Edition
ISBN: 9780134106786
Author: David M. Kroenke, Randall J. Boyle
Publisher: PEARSON
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Expert Solution & Answer
Chapter 5.2, Problem 8EGDQ
a.
Explanation of Solution
Ethical adage on considering both categorical imperative and utilitarian perspective:
The following adage is not ethical as it already know that answers are not required and it indirectly means that it is likely to know that there is a problem already.
- Once it is found that there is a problem then it is necessary to have a so...
b.
Explanation of Solution
Adage is socially responsible:
“No”, the following adage is not a socially responsible.
Reason:
- Most of the social problems are kept aside as a problem because people are not interested in asking difficult questions...
c.
Explanation of Solution
Adage relate to Mrs. M:
- Mrs. M has to process large amount of information to know about the status of the Hispanics and also to find the people who are under paid...
d.
Explanation of Solution
Adage relate to future business professional:
- As a future professional, concentration on actual information will give accurate direction for the work...
e.
Explanation of Solution
Adage relate to organization:
- The adage will help to avoid confusions related with salary package and unwanted compa...
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Methods (Ch6) - Review
1. (The MyRoot method) Below is a manual implementation of the Math.sqrt() method in Java.
There are two methods, method #1 which calculates the square root for positive integers, and
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public class SquareRoot {
public static void main(String[] args) {
}
// implement a loop of your choice here
// Method that calculates the square root of integer variables
public static double myRoot(int number) {
double root;
root=number/2;
double root old;
do {
root old root;
root (root_old+number/root_old)/2;
} while (Math.abs(root_old-root)>1.8E-6);
return root;
}
// Method that calculates the square root of double variables
public static double myRoot(double number) {
double root;
root number/2;
double root_old;
do {
root old root;
root (root_old+number/root_old)/2;
while (Math.abs (root_old-root)>1.0E-6);
return root;
}
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Chapter 5 Solutions
Using MIS (9th Edition)
Ch. 5.2 - Prob. 1EGDQCh. 5.2 - Prob. 2EGDQCh. 5.2 - Prob. 3EGDQCh. 5.2 - Prob. 4EGDQCh. 5.2 - Prob. 5EGDQCh. 5.2 - Prob. 6EGDQCh. 5.2 - Prob. 7EGDQCh. 5.2 - Prob. 8EGDQCh. 5.3 - Prob. 1NWDSCh. 5.3 - Prob. 2NWDS
Ch. 5.3 - Prob. 3NWDSCh. 5.3 - Prob. 4NWDSCh. 5.3 - Prob. 5NWDSCh. 5.8 - Prob. 1SGDQCh. 5.8 - Prob. 2SGDQCh. 5.8 - Prob. 3SGDQCh. 5.8 - Prob. 4SGDQCh. 5.8 - Prob. 5SGDQCh. 5.8 - Prob. 6SGDQCh. 5.8 - Prob. 7SGDQCh. 5.8 - Prob. 1IKDMCh. 5.8 - Prob. 2IKDMCh. 5.8 - Prob. 3IKDMCh. 5.8 - Prob. 4IKDMCh. 5.8 - Prob. 1ARQCh. 5.8 - Prob. 2ARQCh. 5.8 - Prob. 3ARQCh. 5.8 - Prob. 4ARQCh. 5.8 - Prob. 5ARQCh. 5.8 - Prob. 6ARQCh. 5.8 - Prob. 7ARQCh. 5.8 - Prob. 8ARQCh. 5 - Prob. 5.1UYKCh. 5 - Prob. 5.2UYKCh. 5 - Prob. 5.3UYKCh. 5 - Prob. 5.4UYKCh. 5 - Prob. 5.5CE5Ch. 5 - Prob. 5.6CE5Ch. 5 - Prob. 5.7CE5Ch. 5 - Prob. 5.8CE5Ch. 5 - Prob. 5.9CE5Ch. 5 - Prob. 5.10CE5Ch. 5 - Prob. 5.11CE5Ch. 5 - Prob. 5.12CE5Ch. 5 - Prob. 5.13CS5Ch. 5 - Prob. 5.14CS5Ch. 5 - Prob. 5.15CS5Ch. 5 - Prob. 5.16CS5Ch. 5 - Prob. 5.17CS5Ch. 5 - Prob. 5.18CS5Ch. 5 - Prob. 5.19CS5Ch. 5 - Prob. 5.2MMLCh. 5 - Prob. 5.21MML
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