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- The procedure to find the stationary points of a particular function f(x, y) leads to the eq 3x² +18x3y² +27= 0, -6xy +by = 0. The second of these equations has solutions y = 0 or x = 1. Select the option that gives a complete list of the stationary points of the function. Select one: O (-3,0), (1, –4), (1, 4) O (0, -3), (-4, 1), (4, 1) O(1, -3), (-4, 0), (4,0) O(-3, 1), (0, -4), (0, 4)arrow_forward5. The function y₁ = r + 1 is a solution of (1-2-x²)+2(1+z)y-2yy=0. Find the general solution.arrow_forwardThis problem is about the constant coefficient linear inhomogeneous equation p(d/dx)y = f(x) where p(r) = (r + 1)(r− 2)². In the table below, at left are various right sides f(x), and across from that at right is a form of a particular solution yp. For each line determine the constants from a, b, c such that y, is a solution, or state that the given form is not a solution for any such values. A f = x², Yp = ax² B f = x², Ур = ax² + bx, c f = x², f = x²+3x+1, Yp = ax² + bx + c D Yp = ax² + bx + c, E f = e¹, 4x Yp = ae F f = e³, Yp = ae Gf=e³, H_f = e², | f = e², J f = e² Ур = axe 2x ae²z Yp = ae Yp = axe² Ур = az²e²xarrow_forward
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