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- Suppose solving an equation by Laplace transform results in 9 s Y(s) = s2 + 49' Evaluate y(0).arrow_forwardProblem 2 Find dy/dx of y = x* at the point (2,4) by following a similar procedure: 1. Apply In() to both sides of the equation 2. Find y' at (2, 4) by taking the derivative of the equation obtained in step 1, using implicit differentiationarrow_forwardQ3:- (A) Solve the following differential equation: y³ −3y² + 3y" - y" = x² 1 (B) Find the inverse Laplace transform of the given function: F(S) = - (5² + a²)²arrow_forward
- Consider the differential equation 2y"+ ty'-2y = 14, y(0) = y'(0) = 0. In some instances, the Laplace transform can be used to solve linear differential equations with variable monomial coefficients. Use Theorem 7.4.1., THEOREM 7.4.1 Derivatives of Transforms If F(s) = L{ft)} and n = 1, 2, 3,..., then L{"{t} = (-1)F(s), ds" to reduce the given differential equation to a linear first-order DE in the transformed function Ys) = Lly(t)}. Solve the first-order DE for Y(s). Y(s) =| Then find y(t) = Z (Y(s)}. y(t)%Darrow_forwardTransform the differential equation -3y + 4y - 4y = sin(at) y(0) = -4 y = -4 into an algebraic equation by taking the Laplace transform of each side. Therefore Y =arrow_forwardFor the Cauchy-Euler equation x2y''+xy'+y=x2 if you substitute z=ln(x), y'=(1/x)(dy/dz), and y''=(-1/x2)(dy/dz)+(1/x2)(d2y/dz2) into the original equation, it will transform to the equation a(d2y/dz2)+b(dy/dz)+cy=e2z Then a+b+c=? Fill in the equation mark using one of the following answer choices. (a) 0 (b) 1 (c) 2 (d) 3 (e) 4arrow_forward
- For Problems 12 and 14, use the Laplace transform to solve the given initialvalue problem. The correct answer for 12: 10 te^(-5t) The correct answer for 14: -(1/2)sint + 2cost - (1/2)tcost. Please show how to get the correct answer for 12 and 14. thank youarrow_forwardFigure 1.5.8 shows a slope field and typical solution curves for the equation y' = x + y. (a) Show that ev- ery solution curve approaches the straight line y = -x – 1 as x → -00. (b) For each of the five values yı = -10, -5, 0, 5, and 10, determine the initial value yo (accurate to five decimal places) such that y(5) = yı for the solution satisfying the initial condition y(-5) = yo- 10 6. 2 -10 -5 FIGURE 1.5.8. Slope field and solution curves for y' = x + y.arrow_forwardConsider the differential equation 2y" + ty' - 2y = 18, y(0) = y'(0) = 0. In some instances, the Laplace transform can be used to solve linear differential equations with variable monomial coefficients. Use Theorem 7.4.1., THEOREM 7.4.1 Derivatives of Transforms If F(s) = £{f(t)} and n = 1, 2, 3, . . . , then dn -F(s), ds" to reduce the given differential equation to a linear first-order DE in the transformed function Y(s) = £{y(t)}. £{t¹f(t)}: = (-1)^_ Solve the first-order DE for Y(s). Y(s) = Then find y(t) = £¹{Y(s)}. y(t) =arrow_forward
- Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:Cengage