ALGEBRA 1 W/CALCCHAT+CALCVIEW:STUD.ED.

1st Edition

ISBN: 9781644328644

Author: Larson

Publisher: CENGAGE L

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Textbook Question

Chapter 5.4, Problem 4STP

For Exercises $1 − 5 ,$ choose the correct letter.

Chapter 5.4, Problem 4STP, For Exercises 15, choose the correct letter. Which equation represents the line shown in the graph?

Which equation represents the line shown in the graph? $y = − 3 x − 2$

G. $y = 3 x + 2$

H. $y + 4 = − 3 ( x − 2 )$

I. $y + 8 = − 3 ( x − 2 )$

Expert Solution & Answer

To determine

To write the equation represents the line shown in the graph and choose the correct option.

Answer to Problem 4STP

$H. y+4=−3(x−2)$

Explanation of Solution

Given information:

A graph of line as

ALGEBRA 1 W/CALCCHAT+CALCVIEW:STUD.ED. , Chapter 5.4, Problem 4STP

Solution:

From the graph, it can be seen that the line crosses at the y -axis at (0, 2)

So, the y -intercept ( b ) = 2.

Go 6 units downward and 1 unit right then to get a point (2, -4)

Therefore, the slope = $RiseRun=−4−22−0=−62=−3$

So, the slope ( m ) of line is $−3.$

Then plug the value of slope (m) and coordinates (2, -4) in point slope form.

Point slope form: $(y−y1)=m(x−x1)$

$y−(−4)=(−3)(x−2)$

Simplify:

$y+4=−3(x−2)$

Therefore, the equation of given graph of line is $y+4=−3(x−2).$

Chapter 5.4, Problem 3STP

Chapter 5.4, Problem 5STP

Chapter 5 Solutions

ALGEBRA 1 W/CALCCHAT+CALCVIEW:STUD.ED.

Ch. 5.1 - Determine whether each rate of change is constant....Ch. 5.1 - Determine whether each rate of change is constant....Ch. 5.1 - Determine whether each rate of change is constant....Ch. 5.1 - Find the slope of each line.Ch. 5.1 - Find the slope of each line.Ch. 5.1 - Find the slope of each line.Ch. 5.1 - Find the slope of the line that passes through...Ch. 5.1 - Find the slope of the line that passes through...Ch. 5.1 - Find the slope of the line that passes through...Ch. 5.1 - Find the slope of the line that passes through...

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For Exercises 1 − 5 , choose the correct letter. Which equation represents the line shown in the graph? y = − 3 x − 2 G. y = 3 x + 2 H. y + 4 = − 3 ( x − 2 ) I. y + 8 = − 3 ( x − 2 )