Explanation Given: f ( x ) = { 12 − x 2 , for x ≤ 2 x 3 , for x > 2 } Formula used: A r e a = ∫ a b f ( x ) d x , [ a , b ] = F ( b ) − F ( a ) Calculation: ∫ − 2 3 f ( x ) d x = ∫ − 2 2 f ( x ) d x + ∫ 2 3 f ( x ) d x = ∫ − 2 2 ( 12 − x 2 ) d x + ∫ 2 3 x 3 d x = [ 12 x − x

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ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 5.4, Problem 41E

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We need to evaluate $\int_{- 2}^{3} f (x) d x$ where $f (x) = {\begin{cases} 12 - x^{2}, for x \leq 2 \\ x^{3}, for x > 2 \end{cases}}$ .

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Chapter 5.4, Problem 40E

Chapter 5.4, Problem 42E

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CALCULUS (CLOTH)

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We need to evaluate ∫ − 2 3 f ( x ) d x where f ( x ) = { 12 − x 2 , for x ≤ 2 x 3 , for x > 2 } .

Solution Summary: The author explains how to determine the value of 2 3 f (x ) d x.

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We need to evaluate $\int_{- 2}^{3} f (x) d x$ where $f (x) = {\begin{cases} 12 - x^{2}, for x \leq 2 \\ x^{3}, for x > 2 \end{cases}}$ .

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Chapter 5 Solutions

We need to evaluate ∫ − 2 3 f ( x ) d x where f ( x ) = { 12 − x 2 , for x ≤ 2 x 3 , for x &gt; 2 } .

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We need to evaluate ∫ − 2 3 f ( x ) d x where f ( x ) = { 12 − x 2 , for x ≤ 2 x 3 , for x > 2 } .

We need to evaluate $\int_{- 2}^{3} f (x) d x$ where $f (x) = {\begin{cases} 12 - x^{2}, for x \leq 2 \\ x^{3}, for x > 2 \end{cases}}$ .