Let f be a continuous function that can be expressed in polar coordinates as a function of 0 only: that is, f ( x , y ) = h ( θ ) . where ( x , y ) ∈ D = { r , θ } | R 1 ≤ r ≤ R 2 , θ ≤ θ 2 with 0 ≤ R 1 < R 2 , and 0 ≤ θ 1 < θ 2 ≤ 2 π . Show that ∬ D f ( x , y ) d A = 1 2 ( R 2 2 − R 1 2 ) H ( θ 2 ) − H ( θ 1 ) . where H is an antiderivative of h.
Let f be a continuous function that can be expressed in polar coordinates as a function of 0 only: that is, f ( x , y ) = h ( θ ) . where ( x , y ) ∈ D = { r , θ } | R 1 ≤ r ≤ R 2 , θ ≤ θ 2 with 0 ≤ R 1 < R 2 , and 0 ≤ θ 1 < θ 2 ≤ 2 π . Show that ∬ D f ( x , y ) d A = 1 2 ( R 2 2 − R 1 2 ) H ( θ 2 ) − H ( θ 1 ) . where H is an antiderivative of h.
Let f be a continuous function that can be expressed in polar coordinates as a function of 0 only: that is,
f
(
x
,
y
)
=
h
(
θ
)
. where
(
x
,
y
)
∈
D
=
{
r
,
θ
}
|
R
1
≤
r
≤
R
2
,
θ
≤
θ
2
with
0
≤
R
1
<
R
2
, and
0
≤
θ
1
<
θ
2
≤
2
π
. Show that
∬
D
f
(
x
,
y
)
d
A
=
1
2
(
R
2
2
−
R
1
2
)
H
(
θ
2
)
−
H
(
θ
1
)
. where H is an antiderivative of h.
Find the Jacobian for the change of variables defined by x = r cos θ and y = r sin θ.
The vector function
r(t)
(1+2 cos t) i+ 3j+(5 – 2 sin t) k
traces out a circle in 3-space as t varies. De-
termine the radius and center of this circle.
The vector function
r(t)
(5 – 2 sin t) i + (3+ 2 cos t) j + 2 k
-
traces out a circle in 3-space as t varies. In
which plane does this circle lie?
1. plane x
2. plane y
2
3. plane z
= -2
4. plane z
= 2
5. plane x = -2
6. plane y = -2
Elementary Statistics: Picturing the World (7th Edition)
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