Explanation ∫ 0 π cos x d x = [ sin x ] 0 π = sin π − sin 0 = 0 Given: ∫ 0 π cos x d x = 0 Calculation: Graph of c o s x is given below

Calculus - Standalone book

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Question

Chapter 5.2, Problem 3PQ

To determine

Graphically that $\int_{0}^{π} \cos x d x = 0$

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Chapter 5.2, Problem 2PQ

Chapter 5.2, Problem 4PQ

Chapter 5 Solutions

Calculus - Standalone book

Ch. 5.1 - Prob. 1PQ Ch. 5.1 - Prob. 2PQ Ch. 5.1 - Prob. 3PQ Ch. 5.1 - Prob. 4PQ Ch. 5.1 - Prob. 5PQ Ch. 5.1 - Prob. 1E Ch. 5.1 - Prob. 2E Ch. 5.1 - Prob. 3E Ch. 5.1 - Prob. 4E Ch. 5.1 - Prob. 5E

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Graphically that ∫ 0 π cos x d x = 0

Solution Summary: The author explains that the positive area between the graph of y = c o s x and the

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Graphically that $\int_{0}^{π} \cos x d x = 0$

Want to see the full answer?

Chapter 5 Solutions

Graphically that ∫ 0 π cos x d x = 0

Solution Summary: The author explains that the positive area between the graph of y = c o s x and the

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Graphically that ∫0πcosxdx=0

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Graphically that $\int_{0}^{π} \cos x d x = 0$