Explanation Let f be a real function which is continuous on the closed interval [ a , b ] . Let ∫ a b f ( x ) d x be the definite integral of f ( x ) over [ a , b ] . Then m ( b − a ) ≤ ∫ a b f ( x ) d x ≤ M ( b − a ) where, M is the maximum value of f on [ a , b ] and m is the minimum value of f on [ a , b ] Given: f ( x ) = x − 2 sin x and show that 0.2 ≤ ∫ 1 2 f ( x ) d x ≤ 0.9 . Formula used: Let f be a real function which is continuous on the closed interval [ a , b ] . Let ∫ a b f ( x ) d x be the definite integral of f ( x ) over [ a , b ] ...

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Chapter 5, Problem 84CRE

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To Determine:

The graph of $f (x) = x^{- 2} \sin x$ and show that $0.2 \leq \int_{1}^{2} f (x) d x \leq 0.9$ .

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Chapter 5, Problem 83CRE

Chapter 5, Problem 85CRE

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Chapter 5 Solutions

Calculus - Standalone book

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The graph of f ( x ) = x − 2 sin x and show that 0.2 ≤ ∫ 1 2 f ( x ) d x ≤ 0.9 .

Solution Summary: The author explains that f is a real function which is continuous on the closed interval.

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To Determine:

The graph of $f (x) = x^{- 2} \sin x$ and show that $0.2 \leq \int_{1}^{2} f (x) d x \leq 0.9$ .

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Chapter 5 Solutions

The graph of f ( x ) = x − 2 sin x and show that 0.2 ≤ ∫ 1 2 f ( x ) d x ≤ 0.9 .

Solution Summary: The author explains that f is a real function which is continuous on the closed interval.

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To Determine: The graph of f(x)=x−2sinx and show that 0.2≤∫12f(x)dx≤0.9.

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Chapter 5 Solutions

To Determine:

The graph of $f (x) = x^{- 2} \sin x$ and show that $0.2 \leq \int_{1}^{2} f (x) d x \leq 0.9$ .