Explanation Given: d G d t = t − 1 / 2 G ( 9 ) = − 5 Formula used: A r e a = ∫ a b f ( x ) d x , [ a , b ] = F ( b ) − F ( a ) Calculation: G ( 16 ) − G ( 9 ) = ∫ 9 16 G ' ( t ) d t = ∫ 9 16 t − 1 / 2 d t = [ t − 1 / 2 + 1 − 1 / 2

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Chapter 5.4, Problem 48E

To determine

We need to evaluate $G (16)$ where $\frac{d G}{d t} = t^{- 1 / 2}$ and $G (9) = - 5$ .

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Chapter 5.4, Problem 47E

Chapter 5.4, Problem 49E

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Chapter 5 Solutions

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We need to evaluate G ( 16 ) where d G d t = t − 1 / 2 and G ( 9 ) = − 5 .

Solution Summary: The author explains that G ( 16 ) = 3 based on the formula used.

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We need to evaluate $G (16)$ where $\frac{d G}{d t} = t^{- 1 / 2}$ and $G (9) = - 5$ .

Want to see the full answer?

Chapter 5 Solutions

We need to evaluate G ( 16 ) where d G d t = t − 1 / 2 and G ( 9 ) = − 5 .

Solution Summary: The author explains that G ( 16 ) = 3 based on the formula used.

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We need to evaluate G(16)where dGdt=t−1/2and G(9)=−5.

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Chapter 5 Solutions

We need to evaluate $G (16)$ where $\frac{d G}{d t} = t^{- 1 / 2}$ and $G (9) = - 5$ .