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- Consider a right triangle ABC with the right triangle at vertex B. The charges at A, at B, and at C, are known to be 5 mC, 4 mC, and 7 mC, respectively. Given that the side AB is numerically equal to 91, in meters, and AC is thrice AB, find the magnitudes of the force and of the electric field at C.arrow_forwardA thin rod has uniform charge per length z. The distance between point A and point B is 5W and the distance betweer point A and point C is 8W and the distance between point Cand point P is 2W. We introduce an integration variable h with h = 0 chosen to be at point B and the th direction to the left. The small r segment has length dh and charge dq. We want to find the electric field at point P. Draw it out--label the all the lengths and the integration variable! A B C Parrow_forwardWe have calculated the electric field due to a uniformly charged disk of radius R, along its axis. Note that the final result does not contain the integration variable r: R. Q/A 2€0 Edisk (x² +R*)* Edisk perpendicular to the center of the disk Uniform Q over area A (A=RR²) Show that at a perpendicular distance R from the center of a uniformly negatively charged disk of CA and is directed toward the disk: Q/A radius R, the electric field is 0.3- 2€0 4.4.1barrow_forward
- A part of a Gaussian Surface is a square of side length s. A corner of the square is placed the distances from the origin on the y axis. A point charge Q is located at the origin. The edges of the square are either parallel to the x direction or z direction. The image above shows this information. If Q=25 microCoulomb and s= 15 cm, what is the electric field flux through the square? O none of these O 2.82 106 Nm²/C O 7.06 105 Nm²/C O 1.18 105 Nm²/C O 4.71 105 N*m²/Carrow_forwardThe nonuniform charge density of a solid insulating sphere of radius R is given by = cr2 (r R), where c is a positive constant and r is the radial distance from the center of the sphere. For a spherical shell of radius r and thickness dr, the volume element dV = 4r2dr. a. What is the magnitude of the electric field outside the sphere (r R)? b. What is the magnitude of the electric field inside the sphere (r R)?arrow_forwardConsider a uranium nucleus to be sphere of radius R=7.41015 m with a charge of 92e distributed uniformly throughout its volume. (a) is the electric force exerted on an electron when it is 3.01015 m from the center of the nucleus? (b) What is the acceleration of the electron at this point?arrow_forward
- A straight wire of length L has a positive charge Q distributed along its length. Set up the integral with limits and solve it to find the magnitude of the electric field due to the wire at a point located a distance d from one end of the wire along the line extending from the wire. Must show high level of detail in your logic. Must use the left end of the wire as your origin in the x axis. Answer must be in terms of L, d, Q, x, pi and Eo only.arrow_forwardIf the electric field is not collinear with the normal unit vector of the surface, which of the following trigonometric functions is associated to the smallest angle between the electric field and the normal unit vector? O cosecant O cosine; O the answer cannot be found on the other choices; O cotangent;arrow_forwardWe wish to obtain the complete electric field contribution from the above equation, so we integrate it from O to R to obtain E = (x0/ 2. Evaluating the integral will lead us to Qxo 1 1. E= 4 MEGR? Xo (x3 + R?)/ For the case where in Ris extremely bigger than x0. Without other substitutions, the equation above will reduce to E= Q/ Eo)arrow_forward
- Find the electric field of a thin, circular ring of inner radius R1 and outer radius R2 at a distance Z above the central axis of the ring. Assume the ring has a total charge of Q, distributed uniformly over the 2Dsurface. Start this problem from the definition of an electric field for continuous charge distributions.arrow_forwardProblem Using the method of integration, what is the electric field of a uniformly charged thin circular plate (with radius R and total charge Q) at xo distance from its center? (Consider that the surface of the plate lies in the yz plane) Solution A perfect approach to this is to first obtain the E-field produced by an infinitesimal charge component of the charge Q. There will be several approaches to do this, but the most familiar to us is to obtain a very small shape that could easily represent our circular plane. That shape would be a ring. So for a ring whose charge is q, we recall that the electric field it produces at distance x0 is given by E = (1/ )(x0q)/( 24r2) Since, the actual ring (whose charge is dq) we will be dealing with is an infinitesimal part of the circular plane, then, its infinitesimal electric field contribution is expressed as = (1/ )(x0 24 We wish to obtain the complete electric field contribution from the above equation, so we integrate it from 0 to R to…arrow_forwardProblem Using the method of integration, what is the electric field of a uniformly charged thin circular plate (with radius R and total charge Q) at xo distance from its center? (Consider that the surface of the plate lies in the yz plane) Solution A perfect approach to this is to first obtain the E-field produced by an infinitesimal charge component of the charge Q. There will be several approaches to do this, but the most familiar to us is to obtain a very small shape that could easily represent our circular plane. That shape would be a ring. So for a ring whose charge is q, we recall that the electric field it produces at distance x0 is given by E = (1/ )(x0q/ Since, the actual ring (whose charge is dg) we will be dealing with is an infinitesimal part of the circular plane, then, its infinitesimal electric field contribution is expressed as = (1/ )(x0 2. We wish to obtain the complete electric field contribution from the above equation, so we integrate it from 0 to R to obtain E =…arrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning