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Science Chemistry Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)

Medical Use Atomic Symbol Mass Number Number of Protons Number of Neutrons Cancer treatment C 55 131 s Brain scan 43 56 Blood flow 141 58 Bone scan 85 47 Lung function X 54 133 e Solution: Medical Use Atomic Symbol Mass Number Number of Protons Number of Neutrons Cancer treatment C 55 131 s 131 55 76 Brain scan T 43 99 c 99 43 56 Blood flow C 58 141 e 141 58 83 Bone scan S 38 85 r 85 38 47 Lung function X 54 133 e 133 54 79 Given Info: C 55 131 s is used in cancer treatment. The atom used for brain scans has 43 and 56 number of protons and number of neutrons respectively. The element used for blood flow has a mass number and number of protons of 141 and 58 respectively. The element used for bone scan has a mass number and number of neutrons of 85 and 47 respectively. X 54 133 e is used in lung function. Formula used: The atomic symbol of any element is expressed as X Atomic number Mass number , where X is the atom or particle. Mass number = Number of protons + number of neutrons Calculation: From the formula we get the mass number of C 55 131 s and there are 55 protons in its nucleus. The number of protons = Mass number − number of neutrons, 131 - 55 = 58. The atomic number of the element used in brain scan is 43 (as number of protons is equivalent to number of electrons and also it is the atomic number). Thus the element will be technetium (Tc). And mass number = 43 + 56 = 99. The atomic number of the element used in blood flow is 58, thus the element is cerium (Ce). And the number of neutrons = 141 - 58 = 83. The number of proton present in the element used in bone scan is 85 - 47 = 38 (as we get from the formula) and it is its atomic number as well. Thus the element is strontium (Sr). Mass number and atomic number of the element used in lung function is 133 and 54 respectively, so putting the values in the equation we get, number of neutrons 133 - 54 = 79. Conclusion: The mass number, number of protons and number of neutrons present in C 55 131 s is 131, 55 and 76 respectively. The atomic symbol of the element used in brain scan is T 43 99 c which has a mass number of 99. The atomic symbol of the element used in blood flow is C 58 141 e which has 83 neutrons in its nucleus. S 38 85 r is used in bone scan and has 38 protons in its nucleus. The mass number, proton and neutrons of the atom used in lung function is 133, 54 and 79 respectively.

Medical Use Atomic Symbol Mass Number Number of Protons Number of Neutrons Cancer treatment C 55 131 s Brain scan 43 56 Blood flow 141 58 Bone scan 85 47 Lung function X 54 133 e Solution: Medical Use Atomic Symbol Mass Number Number of Protons Number of Neutrons Cancer treatment C 55 131 s 131 55 76 Brain scan T 43 99 c 99 43 56 Blood flow C 58 141 e 141 58 83 Bone scan S 38 85 r 85 38 47 Lung function X 54 133 e 133 54 79 Given Info: C 55 131 s is used in cancer treatment. The atom used for brain scans has 43 and 56 number of protons and number of neutrons respectively. The element used for blood flow has a mass number and number of protons of 141 and 58 respectively. The element used for bone scan has a mass number and number of neutrons of 85 and 47 respectively. X 54 133 e is used in lung function. Formula used: The atomic symbol of any element is expressed as X Atomic number Mass number , where X is the atom or particle. Mass number = Number of protons + number of neutrons Calculation: From the formula we get the mass number of C 55 131 s and there are 55 protons in its nucleus. The number of protons = Mass number − number of neutrons, 131 - 55 = 58. The atomic number of the element used in brain scan is 43 (as number of protons is equivalent to number of electrons and also it is the atomic number). Thus the element will be technetium (Tc). And mass number = 43 + 56 = 99. The atomic number of the element used in blood flow is 58, thus the element is cerium (Ce). And the number of neutrons = 141 - 58 = 83. The number of proton present in the element used in bone scan is 85 - 47 = 38 (as we get from the formula) and it is its atomic number as well. Thus the element is strontium (Sr). Mass number and atomic number of the element used in lung function is 133 and 54 respectively, so putting the values in the equation we get, number of neutrons 133 - 54 = 79. Conclusion: The mass number, number of protons and number of neutrons present in C 55 131 s is 131, 55 and 76 respectively. The atomic symbol of the element used in brain scan is T 43 99 c which has a mass number of 99. The atomic symbol of the element used in blood flow is C 58 141 e which has 83 neutrons in its nucleus. S 38 85 r is used in bone scan and has 38 protons in its nucleus. The mass number, proton and neutrons of the atom used in lung function is 133, 54 and 79 respectively.

Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)

Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)

13th Edition

ISBN: 9780134421353

Author: Karen C. Timberlake

Publisher: PEARSON

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Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)

Ch. 5.1 - Prob. 5.1PP Ch. 5.1 - Prob. 5.2PP Ch. 5.1 - Naturally occurring potassium consists of three...Ch. 5.1 - Naturally occurring iodine is iodine-127....Ch. 5.1 - Identify each of the following: a. 10X b. 24X c....Ch. 5.1 - Identify each of the following: a. 11X b. 3581X c....Ch. 5.1 - Prob. 5.7PP Ch. 5.1 - Prob. 5.8PP Ch. 5.1 - Prob. 5.9PP Ch. 5.1 - Prob. 5.10PP

Ch. 5.1 - Prob. 5.11PP Ch. 5.1 - Prob. 5.12PP Ch. 5.2 - Prob. 5.13PP Ch. 5.2 - Prob. 5.14PP Ch. 5.2 - Prob. 5.15PP Ch. 5.2 - Prob. 5.16PP Ch. 5.2 - Prob. 5.17PP Ch. 5.2 - Prob. 5.18PP Ch. 5.2 - Prob. 5.19PP Ch. 5.2 - Prob. 5.20PP Ch. 5.2 - Complete each of the following reactions: a....Ch. 5.2 - Prob. 5.22PP Ch. 5.3 - Prob. 5.23PP Ch. 5.3 - Prob. 5.24PP Ch. 5.3 - Prob. 5.25PP Ch. 5.3 - Prob. 5.26PP Ch. 5.3 - Prob. 5.27PP Ch. 5.3 - Prob. 5.28PP Ch. 5.4 - Prob. 5.29PP Ch. 5.4 - Prob. 5.30PP Ch. 5.4 - Prob. 5.31PP Ch. 5.4 - Prob. 5.32PP Ch. 5.4 - Prob. 5.33PP Ch. 5.4 - Prob. 5.34PP Ch. 5.5 - Prob. 5.35PP Ch. 5.5 - Prob. 5.36PP Ch. 5.5 - Prob. 5.37PP Ch. 5.5 - Prob. 5.38PP Ch. 5.5 - Prob. 5.39PP Ch. 5.5 - Prob. 5.40PP Ch. 5.6 - Prob. 5.41PP Ch. 5.6 - Prob. 5.42PP Ch. 5.6 - Prob. 5.43PP Ch. 5.6 - Prob. 5.44PP Ch. 5.6 - Prob. 5.45PP Ch. 5.6 - Prob. 5.46PP Ch. 5.6 - Prob. 5.47PP Ch. 5.6 - Prob. 5.48PP Ch. 5.6 - Prob. 5.49PP Ch. 5.6 - Prob. 5.50PP Ch. 5 - Prob. 5.51UTC Ch. 5 - Prob. 5.52UTC Ch. 5 - 5.53 Draw the nucleus of the isotope that is...Ch. 5 - Prob. 5.54UTC Ch. 5 - Prob. 5.55UTC Ch. 5 - Prob. 5.56UTC Ch. 5 - Determine the number of protons and number of...Ch. 5 - Determine the number of protons and number of...Ch. 5 - Prob. 5.59APP Ch. 5 - Prob. 5.60APP Ch. 5 - Prob. 5.61APP Ch. 5 - Prob. 5.62APP Ch. 5 - Prob. 5.63APP Ch. 5 - Prob. 5.64APP Ch. 5 - Prob. 5.65APP Ch. 5 - Prob. 5.66APP Ch. 5 - Prob. 5.67APP Ch. 5 - Prob. 5.68APP Ch. 5 - Prob. 5.69APP Ch. 5 - Prob. 5.70APP Ch. 5 - Where does fusion occur naturally? (5.6)Ch. 5 - Prob. 5.72APP Ch. 5 - Prob. 5.73APP Ch. 5 - Prob. 5.74APP Ch. 5 - Prob. 5.75APP Ch. 5 - Prob. 5.76APP Ch. 5 - Prob. 5.77APP Ch. 5 - Prob. 5.78APP Ch. 5 - Prob. 5.79CP Ch. 5 - Prob. 5.80CP Ch. 5 - Prob. 5.81CP Ch. 5 - Prob. 5.82CP Ch. 5 - Prob. 5.83CP Ch. 5 - Prob. 5.84CP Ch. 5 - Prob. 5.85CP Ch. 5 - Prob. 5.86CP Ch. 5 - Prob. 5.87CP Ch. 5 - Prob. 5.88CP Ch. 5 - Prob. 5.89CP Ch. 5 - Prob. 5.90CP

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