Methanol (CH 4 O), which is used as a fuel in high-performance racing cars, burns in the presence of O 2 to form CO 2 and H 2 O. The molar masses for all substances are given under the balanced equation. 2CH 4 O(l) + 3 O 2 ( g ) → 2 CO 2 (g), + 4H 2 O(g) 32 .04 g/mol 32 .00 g/mol 44 .01 g/mol 18 .02 g/mol What is the theoretical yield of CO 2 from 48.0 g of methanol? What is the percent yield of CO 2 if 48.0 g of CO 2 are formed?
Methanol (CH 4 O), which is used as a fuel in high-performance racing cars, burns in the presence of O 2 to form CO 2 and H 2 O. The molar masses for all substances are given under the balanced equation. 2CH 4 O(l) + 3 O 2 ( g ) → 2 CO 2 (g), + 4H 2 O(g) 32 .04 g/mol 32 .00 g/mol 44 .01 g/mol 18 .02 g/mol What is the theoretical yield of CO 2 from 48.0 g of methanol? What is the percent yield of CO 2 if 48.0 g of CO 2 are formed?
Solution Summary: The author explains how the theoretical yield of CO_2 from 48.0 g of methanol should be predicted.
Methanol
(CH
4
O),
which is used as a fuel in high-performance racing cars, burns in the presence of O2 to form CO2 and H2O. The molar masses for all substances are given under the balanced equation.
2CH
4
O(l)
+
3
O
2
(
g
)
→
2
CO
2
(g), + 4H
2
O(g)
Explain why in the representation of a one-dimensional velocity distribution function for a particular gas, the maximum occurs for vi = 0 m/s.
Explain why the representation of a one-dimensional velocity distribution function for a particular gas becomes flatter as the temperature increases.
Draw a Lewis structure for each of the following molecules and assign
charges where appropriate. The order in which the atoms are connected
is given in parentheses.
a. CIFCIF
b. BrCNBrCN
0
c. SOCI2 × (CISCIO) SOC₁₂ (CISCI)
You can draw both an octet and a valence
shell expanded structure. Considering the following structural information, which
is the better one: The measured S-OS-O bond length in SOC12SOCl2 is 1.43 Å.
For comparison, that in SO2SO2 is 1.43 Å [Exercise 1-9, part (b)], that in
CHзSOHCH3 SOH
d. CH3NH2CH3NH2
(methanesulfenic acid) is 1.66 A.
e. CH3OCH3 CH3 OCH3
NH2
f. N2H2× (HNNH) N2 H2 (HNNH)
g. CH2COCH₂ CO
h. HN3× (HNNN) HN3 (HNNN)
i. N20 × (NNO) N2O (NNO)
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