EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM
EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM
8th Edition
ISBN: 9780134554433
Author: CORWIN
Publisher: PEARSON CO
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Chapter 5, Problem 77E
Interpretation Introduction

(a)

Interpretation:

The electron configuration for Mg2+ ion with the help of periodic table is to be predicted.

Concept introduction:

Ionic charge is defined as the charge possesses by an ion that result by the gain or loss of an electron by an atom or a molecule. Metals are electropositive in nature because they loss electrons from their outermost shells. Nonmetals are electronegative in nature because they gain electrons in their outermost shells.

Expert Solution
Check Mark

Answer to Problem 77E

The predicted electronic configuration of Mg2+ is 1s22s22p6.

Explanation of Solution

The given positive ion is Mg2+.

Magnesium belongs to the group 2 of a periodic table. The atomic number of magnesium is 12. The atomic number corresponds to the number of electrons present in an element. Electronic configuration tells about the arrangement of an electron in each subshell and orbit of an atom. The electronic configuration of Mg is 1s22s22p63s2. It loss two electrons and act as an Mg2+ ion. Therefore, the predicted electronic configuration of Mg2+ is 1s22s22p6.

Conclusion

The predicted electronic configuration of Mg2+ is 1s22s22p6.

Interpretation Introduction

(b)

Interpretation:

The electron configuration for K+ ion with the help of periodic table is to be predicted.

Concept introduction:

Ionic charge is defined as the charge possesses by an ion that result by the gain or loss of an electron by an atom or a molecule. Metals are electropositive in nature because they loss electrons from their outermost shells. Nonmetals are electronegative in nature because they gain electrons in their outermost shells.

Expert Solution
Check Mark

Answer to Problem 77E

The predicted electronic configuration of K+ is 1s22s22p63s23p6.

Explanation of Solution

The given positive ion is K+.

Potassium belongs to the group 1 of a periodic table. The atomic number of potassium is 19. The atomic number corresponds to the number of electrons present in an element. Electronic configuration tells about the arrangement of an electron in each subshell and orbit of an atom. The electronic configuration of K is 1s22s22p63s23p64s1. It loss one electrons and act as an K+ ion. Therefore, the predicted electronic configuration of K+ is 1s22s22p63s23p6.

Conclusion

The predicted electronic configuration of K+ is 1s22s22p63s23p6.

Interpretation Introduction

(c)

Interpretation:

The electron configuration for Fe2+ ion with the help of periodic table is to be predicted.

Concept introduction:

Ionic charge is defined as the charge possesses by an ion that result by the gain or loss of an electron by an atom or a molecule. Metals are electropositive in nature because they loss electrons from their outermost shells. Nonmetals are electronegative in nature because they gain electrons in their outermost shells.

Expert Solution
Check Mark

Answer to Problem 77E

The predicted electronic configuration of Fe2+ is 1s22s22p63s23p64s23d6.

Explanation of Solution

The given positive ion is Fe2+.

Iron belongs to the group 8 of a periodic table. The atomic number of iron is 26. The atomic number corresponds to the number of electrons present in an element. Electronic configuration tells about the arrangement of an electron in each subshell and orbit of an atom. The electronic configuration of Fe is 1s22s22p63s23p64s23d6. It loss two electrons and act as an Fe2+ ion. Therefore, the predicted electronic configuration of Fe2+ is 1s22s22p63s23p64s23d6.

Conclusion

The predicted electronic configuration of Fe2+ is 1s22s22p63s23p64s23d6.

Interpretation Introduction

(d)

Interpretation:

The electron configuration for Zr2+ ion with the help of periodic table is to be predicted.

Concept introduction:

Ionic charge is defined as the charge possesses by an ion that result by the gain or loss of an electron by an atom or a molecule. Metals are electropositive in nature because they loss electrons from their outermost shells. Nonmetals are electronegative in nature because they gain electrons in their outermost shells.

Expert Solution
Check Mark

Answer to Problem 77E

The predicted electronic configuration of Zr2+ is 1s22s22p63s23p64s23d8.

Explanation of Solution

The given positive ion is Zr2+.

Zinc belongs to the group 12 of a periodic table. The atomic number of zinc is 30. The atomic number corresponds to the number of electrons present in an element. Electronic configuration tells about the arrangement of an electron in each subshell and orbit of an atom. The electronic configuration of Zr is 1s22s22p63s23p64s23d10. It loss two electrons and act as an Zr2+ ion. Therefore, the predicted electronic configuration of Zr2+ is 1s22s22p63s23p64s23d8.

Conclusion

The predicted electronic configuration of Zr2+ is 1s22s22p63s23p64s23d8.

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Chapter 5 Solutions

EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM

Ch. 5 - Prob. 11CECh. 5 - Prob. 12CECh. 5 - Prob. 13CECh. 5 - Prob. 14CECh. 5 - Prob. 1KTCh. 5 - Prob. 2KTCh. 5 - Prob. 3KTCh. 5 - Prob. 4KTCh. 5 - Prob. 5KTCh. 5 - Prob. 6KTCh. 5 - Prob. 7KTCh. 5 - Prob. 8KTCh. 5 - Prob. 9KTCh. 5 - Prob. 10KTCh. 5 - Prob. 11KTCh. 5 - Prob. 12KTCh. 5 - Prob. 13KTCh. 5 - Prob. 14KTCh. 5 - Prob. 15KTCh. 5 - Prob. 16KTCh. 5 - Prob. 17KTCh. 5 - Prob. 18KTCh. 5 - Prob. 19KTCh. 5 - Prob. 20KTCh. 5 - Prob. 21KTCh. 5 - Prob. 22KTCh. 5 - Prob. 23KTCh. 5 - Prob. 1ECh. 5 - Prob. 2ECh. 5 - Prob. 3ECh. 5 - Prob. 4ECh. 5 - Prob. 5ECh. 5 - Prob. 6ECh. 5 - Prob. 7ECh. 5 - Prob. 8ECh. 5 - Prob. 9ECh. 5 - Prob. 10ECh. 5 - Prob. 11ECh. 5 - Prob. 12ECh. 5 - Prob. 13ECh. 5 - Prob. 14ECh. 5 - Prob. 15ECh. 5 - Prob. 16ECh. 5 - Prob. 17ECh. 5 - Prob. 18ECh. 5 - Prob. 19ECh. 5 - Prob. 20ECh. 5 - Prob. 21ECh. 5 - Prob. 22ECh. 5 - Prob. 23ECh. 5 - Prob. 24ECh. 5 - Prob. 25ECh. 5 - Prob. 26ECh. 5 - Prob. 27ECh. 5 - Prob. 28ECh. 5 - Prob. 29ECh. 5 - Prob. 30ECh. 5 - Prob. 31ECh. 5 - Prob. 32ECh. 5 - Prob. 33ECh. 5 - Prob. 34ECh. 5 - Prob. 35ECh. 5 - Prob. 36ECh. 5 - Prob. 37ECh. 5 - Prob. 38ECh. 5 - Prob. 39ECh. 5 - Prob. 40ECh. 5 - Prob. 41ECh. 5 - Prob. 42ECh. 5 - Prob. 43ECh. 5 - Prob. 44ECh. 5 - Prob. 45ECh. 5 - Prob. 46ECh. 5 - Prob. 47ECh. 5 - Prob. 48ECh. 5 - Prob. 49ECh. 5 - Prob. 50ECh. 5 - Prob. 51ECh. 5 - Prob. 52ECh. 5 - Prob. 53ECh. 5 - Prob. 54ECh. 5 - Prob. 55ECh. 5 - Prob. 56ECh. 5 - Prob. 57ECh. 5 - Prob. 58ECh. 5 - Prob. 59ECh. 5 - Prob. 60ECh. 5 - Prob. 61ECh. 5 - Prob. 62ECh. 5 - Prob. 63ECh. 5 - Prob. 64ECh. 5 - Prob. 65ECh. 5 - Prob. 66ECh. 5 - Prob. 67ECh. 5 - Prob. 68ECh. 5 - Prob. 69ECh. 5 - Prob. 70ECh. 5 - Prob. 71ECh. 5 - Prob. 72ECh. 5 - Prob. 73ECh. 5 - Prob. 74ECh. 5 - Prob. 75ECh. 5 - Prob. 76ECh. 5 - Prob. 77ECh. 5 - Prob. 78ECh. 5 - Prob. 79ECh. 5 - Prob. 80ECh. 5 - Prob. 81ECh. 5 - Prob. 82ECh. 5 - Prob. 83ECh. 5 - Prob. 84ECh. 5 - Prob. 85ECh. 5 - Prob. 86ECh. 5 - Prob. 87ECh. 5 - Prob. 88ECh. 5 - Prob. 89ECh. 5 - Prob. 90ECh. 5 - Prob. 91ECh. 5 - Prob. 92ECh. 5 - Prob. 1STCh. 5 - Prob. 2STCh. 5 - Prob. 3STCh. 5 - Prob. 4STCh. 5 - Prob. 5STCh. 5 - Prob. 6STCh. 5 - Prob. 7STCh. 5 - Prob. 8STCh. 5 - Prob. 9STCh. 5 - Prob. 10STCh. 5 - Prob. 11STCh. 5 - Prob. 12STCh. 5 - Prob. 13STCh. 5 - Prob. 14STCh. 5 - Prob. 15STCh. 5 - Prob. 16STCh. 5 - Prob. 17STCh. 5 - Prob. 18ST
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