Chapter 5, Problem 73QP

Interpretation Introduction

Interpretation:

The change in internal energy for the given reaction under the given conditions is to be calculated.

Concept introduction:

The amount of work done by a pressure–volume work process is calculated as follows:

$w=-P\Delta V$

Here, $P$ is the external pressure and $\Delta V$ is the change in volume.

The change in enthalpy for any process is calculated as follows:

$\Delta H=\Delta U-w$

Here, $\Delta H$ is the enthalpy change, $\Delta U$ is the change in internal energy, and w is the work done.