EBK 3I-EBK: WELDING PRINCIPLES & APPLIC
8th Edition
ISBN: 9780176919764
Author: Jeffus
Publisher: VST
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Textbook Question
Chapter 5, Problem 6R
Why must the ends of pipe be beveled before being welded?
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A punch press with flywheel adequate to minimize speed fluctuation produces 120 punching strokes per minute, each providing an average force of 2000 N over a stroke of 50 mm. The press is driven through a gear reducer by a shaft rotating 200 rpm. Overall efficiency is 80%. a) What power (W) is transmitted through the shaft? b) What average torque is applied to the shaft?
1.58 The crankshaft of a single-cylinder air compressor rotates 1800 rpm. The piston area is 2000 mm2 and the piston stroke is 50 mm. Assume a simple “idealized” case where the average gas pressure acting on the piston during the compression stroke is 1 MPa, and pressure during the intake stroke is negligible. The compressor is 80% efficient. A flywheel provides adequate control of the speed fluctuation. a) What motor power (kW) is required to drive the crankshaft? b) What torque is transmitted through the crankshaft?
28. The shaft shown in Figure P5-28 is supported by bear-
ings at each end, which have bores of 20.0 mm. Design
the shaft to carry the given load if it is steady and the
shaft is stationary. Make the dimension a as large as pos-
sible while keeping the stress safe. Determine the required
d
20 mm
5.4 kN
d
D = ?
Length not
to scale
-α =
=
-125 mm
20 mm
a =
-250 mm-
FIGURE P5-28 (Problems 28, 29, and 30)
Chapter 5 Solutions
EBK 3I-EBK: WELDING PRINCIPLES & APPLIC
Ch. 5 - List some applications that use low-pressure...Ch. 5 - List some applications that use medium-pressure...Ch. 5 - List some applications that use high-pressure...Ch. 5 - Describe the differences between pipe and tubing.Ch. 5 - What are the advantages of welded piping systems...Ch. 5 - Why must the ends of pipe be beveled before being...Ch. 5 - How can the ends of a pipe be beveled?Ch. 5 - Why is the end of a pipe beveled at a 371/2 angle?Ch. 5 - What causes root suck-back or a concave root face?Ch. 5 - Why are arc strikes outside the welding zone...
Ch. 5 - What are the purposes of backing rings?Ch. 5 - What is the purpose of a hot pass?Ch. 5 - Why must the weld crater be cleaned before...Ch. 5 - What is the maximum width of the cover pass? Why?Ch. 5 - When is the 1G welding position used?Ch. 5 - What can make welding in the 2G vertical fixed...Ch. 5 - What supports the welds on a 2G pipe joint?Ch. 5 - On 5G welds, what usually determines the direction...Ch. 5 - What angle is the pipe at in the 6G position?Ch. 5 - In addition to continuously changing the weld...
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- A carbon steel ball with 27.00-mm diameter is pressed together with an aluminum ball with a 36.00-mm diameter by a force of 11.00 N. Determine the maximum shear stress and the depth at which it will occur for the aluminum ball. Assume the figure given below, which is based on a typical Poisson's ratio of 0.3, is applicable to estimate the depth at which the maximum shear stress occurs for these materials. 1.0 0.8 Ratio of stress to Pma 9 0.6 στ 24 0.4 Tmax 0.2 0 0.5a a 1.5a Z 2a 2.5a За Distance from contact surface The maximum shear stress is determined to be MPa. The depth in the aluminum ball at which the maximum shear stress will occur is determined to be [ mm.arrow_forwardShow all work pleasearrow_forwardDraw top, side, front view With pen(cil) and paper Multi view drawing and handwriting all of itarrow_forward
- A wheel of diameter 150.0 mm and width 37.00 mm carrying a load 2.200 kN rolls on a flat rail. Take the wheel material as steel and the rail material as cast iron. Assume the figure given, which is based on a Poisson's ratio of 0.3, is applicable to estimate the depth at which the maximum shear stress occurs for these materials. At this critical depth, calculate the Hertzian stresses σr, σy, σz, and Tmax for the wheel. 1.0 0.8 0, т Ratio of stress to Pmax 0.4 0.6 90 69 0.2 0.5b b 1.5b Tmax 2b Distance from contact surface The Hertizian stresses are as follows: 02 = or = -23.8 psi for the wheel =| necessary.) σy for the wheel =| MPa σz for the wheel = MPa V4 for the wheel = | MPa 2.5b ཡི 3b MPa (Include a minus sign ifarrow_forwardOnly question 3arrow_forwardOnly question 2arrow_forward
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